How iterate over all the values in an array in Django

Question

I have an array of names in python, which I would like to display using Django templates. I know that tags can be used that support for loops, but they have a unique syntax which I am unfamiliar with.

Also I do not want to use instance.0, instance.1 and so on. I need to be scalable for any size array

Django Template code

(:,

{% for name  in instance  %}
       {{instance}}         
{%endfor%}

 My name is {{my_name}}.
(:,

Python code

from django.template import Template, Context
from django.conf import settings

settings.configure()


t=Template(The above section)
dtype={'names': ['name','offset'],
       'formats':['U20,U20']
       }

instance = np.zeros(5,dtype='U20')
instance[0]=('John')
instance[1]=('Tim')
instance[2]=('Sarah')

name="adrian"


c=Context({"instance":instance, "my_name":name})
print(t.render(c))

Current output

(:,

                [&#39;John&#39; &#39;Tim&#39; &#39;Sarah&#39; &#39;&#39; &#39;&#39;]


                [&#39;John&#39; &#39;Tim&#39; &#39;Sarah&#39; &#39;&#39; &#39;&#39;]


                [&#39;John&#39; &#39;Tim&#39; &#39;Sarah&#39; &#39;&#39; &#39;&#39;]


                [&#39;John&#39; &#39;Tim&#39; &#39;Sarah&#39; &#39;&#39; &#39;&#39;]


                [&#39;John&#39; &#39;Tim&#39; &#39;Sarah&#39; &#39;&#39; &#39;&#39;]


       My name is adrian.
       ).

Desired output

(:,
        i=0

               [John]


               [Tim]


               [Sarah]




       My name is adrian.
       ).

instead of {{instance}}, output {{name}}

Pynchia
– Pynchia

2015-10-21 21:53:04 +00:00
Commented Oct 21, 2015 at 21:53 — Pynchia
– Pynchia, Commented Oct 21, 2015 at 21:53

Pynchia · Accepted Answer · 2015-10-22 20:58:43Z

1

You are outputting the queryset/iterable, i.e. instance.

Instead, you need to output each element of it, which is name, as you correctly state in the for loop.

The syntax of the for is the same as python's (see if this helps)

so just replace

{{instance}}

with

{{name}}

in the template and you should get the desired output

That means the template should be

(:,

{% for name  in instance  %}
       {{name}}
{% endfor %}

 My name is {{my_name}}.
(:,

By the way, I can see the queryset has five elements (the same line was repeated five times because the loop ran on five elements), but the last two lack a name since only John, Tim and Sarah appear.

edited Oct 22, 2015 at 20:58

answered Oct 21, 2015 at 21:55

Pynchia

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5 Comments

GoldenEagle Over a year ago

Thank you! Now I have a new use case. How can I have a for loop print out values from 2 different arrays? Like { for name in instance} {{name}} {{Last_name}}

Pynchia Over a year ago

to iterate over two different sequences pairing the elements form each, you can use zip. e.g. {% for name, last_name in zip(arr1, arr2) %} {{ name }} {{ last_name }} {% endfor %}

GoldenEagle Over a year ago

I don't think it's possible to access zip from within the for loop.All computations have to be done outside the template. Also I think this is my question asked in a better way. stackoverflow.com/questions/33286510/…

GoldenEagle Over a year ago

Ok, but then how do I use the Context() method with the combined arrays?

Pynchia Over a year ago

I am looking at your new question. Maybe you there is no need to change much. See my comment there

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