AttributeError: 'tuple' object has no attribute 'split' with result of input()?

Question

(This is Homework) Here is what I have:

L1 = list(map(int, input().split(",")))

I am running into

  File "lab3.py", line 23, in <module>
    L1 = list(map(int, input().split(",")))
AttributeError: 'tuple' object has no attribute 'split'

what is causing this error?

I am using 1, 2, 3, 4 as input

what do input for input()? it is reading it as a tuple, not a list. — R Nar
– R Nar, Commented Oct 22, 2015 at 23:32
if this is python2, use raw_input instead of input. Please break the problem down before posting. What is the smallest program you can write that still demonstrates your problem? — Ryan Haining
– Ryan Haining, Commented Oct 22, 2015 at 23:34
Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation. MCVE applies here. Please give us the missing code; input might help, too. — Prune
– Prune, Commented Oct 22, 2015 at 23:36
@RyanHaining I have used that before, and apparently it was just a bunch of lucky guesses. — Leb
– Leb, Commented Oct 22, 2015 at 23:54

Ryan Haining · Accepted Answer · 2018-10-27 20:52:47Z

7

You need to use raw_input instead of input

raw_input().split(",")

In Python 2, the input() function will try to eval whatever the user enters, the equivalent of eval(raw_input()). When you input a comma separated list of values, it is evaluated as a tuple. Your code then calls split on that tuple:

>>> input().split(',')
1,2
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'tuple' object has no attribute 'split'

If you want to se that it's actually a tuple:

>>> v = input()
1,3,9
>>> v[0]
1
>>> v[1]
3
>>> v[2]
9
>>> v
(1, 3, 9)

Finally, rather than list and map you'd be better off with a list comprehension

L1 = [int(i) for i in raw_input().split(',')]

edited Oct 27, 2018 at 20:52

answered Oct 22, 2015 at 23:45

Ryan Haining

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