submit dynamic form with javascript

Question

When I want to submit a form with my js i always get this error:

Uncaught TypeError: Cannot read property 'submit' of null

its like the js doesnt find the form

Here the js code:

echo "<script language='javascript' type='text/javascript'>";
echo "function send(ak,id){";
echo   "document.getElementById('java').submit(); ";
echo "document.write('submited');";
echo"}";
echo "</script>";

And here the php / html:

   echo "<form id='java' method='post' action='reisegruppe.php' >";
   echo "<input name='ak' type='hidden' />";
   echo "<input name='id' type='hidden' />";    
    
// Reisegruppe ausgeben
if ($result1->num_rows > 0) {
    // Reisegruppe ID , von , nach ausgeben
    $count = 1;
    while($row1 = $result1->fetch_assoc()) {
        
        echo "<br>" . "id: " . $row1["reisegruppe_id"]. 
             " - <b> von: </b> " .'<b>'.'<input name="von" value='.$row1["von"].' size="5" />'.'</b>'. " " .
             "<b>nach: </b>" .'<b>'.'<input size="5" name="nach" value='. $row1["nach"].'>'.'</b>'." ". "<br>";
     
        echo "<a href='javascript:send(1,32)';>neu eintragen</a>";
        
      
        while($row = $result->fetch_assoc()){     
            if($row1["reisegruppe_id"] == $row["FK_reisegruppe_id"]){                
           echo  " - Name: " . $row["vorname"]. " " . $row["nachname"]. " " . "<br>";}    
        }
        
        $sql = "SELECT reisegruppe_id, von, nach,teilnehmer_id, vorname, nachname,FK_reisegruppe_id FROM Reisegruppe JOIN Teilnehmer on FK_reisegruppe_id = reisegruppe_id";
$result = $conn->query($sql);
          
    }
    
} else {
    echo "0 results";
}


echo </form>;

The last PHP line should be echo '</form>'; otherwise the form is not completed and does not exist. — Hasse Björk
– Hasse Björk, Commented Oct 27, 2015 at 9:25
are you executing your javascript code BEFORE the form was't actually created. Or after form — Nuriddin Rashidov
– Nuriddin Rashidov, Commented Oct 27, 2015 at 9:35
im executing it with the link : echo "<a href='javascript:send(1,32)';>neu eintragen</a>"; there the form already exists — simplesystems
– simplesystems, Commented Oct 27, 2015 at 9:42
echo "document.write('submited');"; remove this line and ur function is good to go.. — Qaisar Satti
– Qaisar Satti, Commented Oct 27, 2015 at 9:47

Qaisar Satti · Accepted Answer · 2015-10-27 10:29:43Z

2

comment this line because it is stop the from from submitting

echo "document.write('submited');";

answered Oct 27, 2015 at 10:29

Qaisar Satti

2,7622 gold badges20 silver badges36 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

submit dynamic form with javascript

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related