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I use the the following pattern in preg_replace() to replace a specific domain name from the beginning of all paths in html file. Everything is fine, but the problem is that it replaces the domain names in email addresses also.

preg_replace('%(https?://)?(www\.)?domain\.com/?%im', '', '$html')

Result shold be like:

domain.com/path/ => /path/
www.domain.com/path/ => /path/
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  • Can you clarify what you mean by beginning of file path in html file; or provide a functional example string? Also the m modifier isn't doing anything in your expression. Commented Oct 30, 2015 at 16:19
  • Something like: %(https?://)?(?<!@)(www\.)?domain\.com/?%im negating the @? Commented Oct 30, 2015 at 16:21
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    you made the protocol portion optional, so there's no way for the regex to tell between example.com-the-email-address and example.com-the-web-url Commented Oct 30, 2015 at 16:23
  • @AbraCadaver that works somehow. Commented Oct 30, 2015 at 16:26
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    You don't need the + although https://https://www.domain.com would be strange. The ? made it optional; just removing that requires it be present once. Commented Oct 30, 2015 at 16:30

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If you want to replace:

But not email address with that domain then you need to use a negative lookbehind for the @ that is required in an email address:

'%(https?://)?(?<!@)(www\.)?domain\.com/?%im'

You don't need the m modifier and if you don't want to replace the trailing / then remove it:

'%(https?://)?(?<!@)(www\.)?domain\.com%i'
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