Is there any way to iterate through a java Hashmap and print out all the values for every key that is a part of the Hashmap?
7 Answers
Yes, you do this by getting the entrySet() of the map. For example:
Map<String, Object> map = new HashMap<String, Object>();
// ...
for (Map.Entry<String, Object> entry : map.entrySet()) {
System.out.println("key=" + entry.getKey() + ", value=" + entry.getValue());
}
(Ofcourse, replace String and Object with the types that your particular Map has - the code above is just an example).
Comments
With for-each loop, use Map.keySet() for iterating keys, Map.values() for iterating values and Map.entrySet() for iterating key/value pairs.
Note that all these are direct views to the map that was used to acquire them so any modification you make to any of the three or the map itself will reflect to all the others too.
Comments
public class abcd {
public static void main(String[] args)
{
Map<Integer, String> testMap = new HashMap<Integer, String>();
testMap.put(10, "a");
testMap.put(20, "b");
testMap.put(30, "c");
testMap.put(40, "d");
for (Entry<Integer, String> entry : testMap.entrySet()) {
Integer key=entry.getKey();
String value=entry.getValue();
}
}
}
Comments
hashmap.keySet().iterator()
use a for loop to iterate it.
then use hashmap.get(item) to get individual values,
Alternatively just use entrySet() for getting an iterator for values.
1 Comment
hashmap.values().iterator().Keep it simple, please:
HashMap<String,String> HeyHoLetsGo = new HashMap();
HeyHoLetsGo.put("I", "wanna be your dog");
HeyHoLetsGo.put("Sheena", "is a punk rocker");
HeyHoLetsGo.put("Rudie", "can't fail");
for ( String theKey : HeyHoLetsGo.keySet() ){
System.out.println(theKey + " "+HeyHoLetsGo.get(theKey));
}
Comments
Java 8 added Map.forEach which you can use like this:
map.forEach((k, v) -> System.out.println("key=" + k + " value=" + v));
There's also replaceAll if you want to update the values:
map.replaceAll((k, v) -> {
int newValue = v + 1;
System.out.println("key=" + k + " value=" + v + " new value=" + newValue);
return newValue;
});