Converting char to ascii value

Question

I know it is stupid question but it does not resolve, and I am googling but that didn't help either. I want to select the sub string from my string and then convert it to ASCII value, but it shows me an error:

int a=char(S.substr(i-1,1));
        int b=S.substr(i ,1);
      if (( a== 13) && (b== 10))
        break;

this is my error :

pdusms.cpp:1020: error: invalid cast from type 'std::basic_string' to type 'char' int a=char(S.substr(i-1,1));
pdusms.cpp:1021: error: invalid conversion from 'const char*' to 'int' [-fpermissive] int b=S.substr(i ,1).c_str(); ^
How can i do that? how can i change the char to int (show ASCII value)

@OzairKafray c_str returns a pointer. That's not convertible to char. — flogram_dev
– flogram_dev, Commented Nov 2, 2015 at 9:57

molbdnilo · Accepted Answer · 2015-11-02 09:18:51Z

2

The result of substr is a string, not a character.
A one-character string is not a character.

Use indexing to get the characters.

You want

int a = S[i-1];
int b = S[i];

but if you're looking for line delimiters you shouldn't compare to ASCII values - use

if (S[i-1] == '\r' && S[i] == '\n')

which is portable.

answered Nov 2, 2015 at 9:18

molbdnilo

67.1k3 gold badges46 silver badges90 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Converting char to ascii value

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related