Strings and user input C++

Question

I'm supposed to read an integer n from the user, which is the followed by n words, and then what follows after that is a sequence of words and punctuation terminated by the word END. For example:

2 foo d  
foo is just food without the d . END

The n words are to be "redacted" from the second line. So it would show up as:

*** is just food without the * .

I think I can figure out the redacting part. I just cannot seem to figure out how to read the words in... any help is much appreciated!

#include <iostream>
#include <string>
using namespace std;

int main()
{
int n;
cin >> n;

string *redact = new string[n]
for(int i = 0; i < n; ++i)
    cin >> redact[i] // this part works!

return 0;
}

@AntiHeadshot No panic, just stated the fact. OP should post their real code. — πάντα ῥεῖ
– πάντα ῥεῖ, Commented Nov 4, 2015 at 11:52

g-217 · Accepted Answer · 2015-11-04 12:18:39Z

2

Following code will cater the purpose.

#include <iostream>
#include <string>
#include <set>

int main()
{
  int n;
  std::cin >> n;

  std::set<std::string> redact;
  std::string word;
  for(int i = 0; i < n; ++i)
  {
    std::cin >> word;
    redact.insert(word);
  }
 while( std::cin>> word && word != "END" )
 { 
     if ( redact.find(word) == redact.end() )
        std::cout<<word<<' ';
 }
 std::cout<<'\n';
return 0;
}

I believe you are a learning C++, please note a point use typesafe, bound-safe and scope-safe C++.

So, no new delete unless you can call yourself an adept. Use the algorithms and containers provided by C++, instead of inventing your own.

answered Nov 4, 2015 at 12:18

g-217

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