String interpolation for built-in functions

Question

I have something like this in PHP

$file = "$dir/" . basename($url);

basename is a built-in function. Is there a way I can use string interpolation syntax for concatenation instead of . syntax?

For member functions of a class, this works:

$file = "$dir/ {$this->someFunc($url)}";

How do I similarly specify internal functions in quoted strings? Just learning.

Not cleanly, interpolation works on variables; but function calls aren't the same as variables — Mark Baker
– Mark Baker, Commented Nov 9, 2015 at 10:53
You could create a class wrapper that would do the function call for you — Mark Baker
– Mark Baker, Commented Nov 9, 2015 at 10:55
Alright. I expected there has to be a syntax since something like "{$x->y()}" works. Thanks. — nawfal
– nawfal, Commented Nov 9, 2015 at 10:56
@MarkBaker: Assigning the function name to a variable works, though. But you really shouldn't write that kind of messy code — Elias Van Ootegem
– Elias Van Ootegem, Commented Nov 9, 2015 at 10:57
@EliasVanOotegem - True. I'd been thinking of something like: class functionCaller { public static function caller($function, ...$args) { return call_user_func_array($function, $args); } } $fc = new functionCaller(); $file = "$dir/{$fc->caller('basename',$url)}" — Mark Baker
– Mark Baker, Commented Nov 9, 2015 at 11:00

Elias Van Ootegem · Accepted Answer · 2015-11-09 11:06:32Z

4

You could do it like so:

$foo = 'bar';

$func = "strtoupper";
echo "test: {$func($foo)}";
//or for assignments:
$path = sprintf(
    '%s/%s',
    $dir,
    basename($file)
);

example here

But really, you shouldn't: it obfuscates what you're actually doing, and makes a trivial task look a lot more complex than it really is (debugging and maintaining this kind of code is a nightmare).
I personally prefer to keep the concatenation, or -if you want- use printf here:

printf(
    'Test: %s',
    strtoupper($foo)
);

edited Nov 9, 2015 at 11:06

answered Nov 9, 2015 at 10:56

Elias Van Ootegem

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