Generate following subsets from list in efficient/pythonic manner

Question

From the list [1,2,3,4] I would like to get [[1],[1,2],[1,2,3],[1,2,3,4]]. I'm not sure what this is called (if anything), perhaps something like following subsets?

My current approach is:

def following_subsets(parts):
    following_subsets = []
    for i in range(1, len(parts)):
        following_subsets.append(parts[:-i])
    return following_subsets

Is there a more efficient way of doing this, or a more pythonic way? Perhaps utilising iterators in some fashion?

you could make it a list comprehension ... but other than being a more pythonc one liner there isnt much benifit — Joran Beasley
– Joran Beasley, Commented Nov 12, 2015 at 23:53

John Kugelman · Accepted Answer · 2015-11-12 23:53:26Z

4

>>> l = [1, 2, 3, 4]
>>> [l[:i+1] for i in range(len(l))]
[[1], [1, 2], [1, 2, 3], [1, 2, 3, 4]]

answered Nov 12, 2015 at 23:53

John Kugelman

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