console.log prints only one line in javascript?

Question

I want to print something like:

#
##
###
####
#####
######
#######

My code is:

<html>
<head>
    <title>Learning Javascript</title>
</head>
<body>


<script type="text/javascript">
    for (var i = 1; i <= 7; i++) {
        for ( var j = 1 ; j <= i ; j++ )
        {
            console.log("#");
        }
    }
</script>
</body>
</html>

It gives only a single #:

Why am I not getting expected output in console log? I have tried both chrome and firebug.

it'll give a single # 28 times, is that right

Jaromanda X
– Jaromanda X

2015-11-13 02:56:29 +00:00
Commented Nov 13, 2015 at 2:56 — Jaromanda X
– Jaromanda X, Commented Nov 13, 2015 at 2:56
Yes.... I am getting something like that.

learner
– learner

2015-11-13 03:08:50 +00:00
Commented Nov 13, 2015 at 3:08 — learner
– learner, Commented Nov 13, 2015 at 3:08

pushkin · Accepted Answer · 2015-11-13 03:22:54Z

7

Actually, I believe you're getting 28 of them, but the console "merges" them into one.

In any event, your code is printing # on a separate line each time. You want to concatenate j #s and print that in the outer for loop.

Alternatively, you can do this:

for (var i = 1; i <= 7; i++) {
    console.log("#".repeat(i));
}

edited Nov 13, 2015 at 3:22

answered Nov 13, 2015 at 2:57

pushkin

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Comments

Anik Islam Abhi · Accepted Answer · 2015-11-13 03:07:11Z

3

In console same value will be counted instead of printing separately

If you wanna to to print separately then concat as string then print

Try like this

for (var i = 1; i <= 7; i++) {
    var str="";
    for (var j = 1; j <= i; j++) {
       str+="#"
    }
    console.log(str);
}

JSFIDDLE

answered Nov 13, 2015 at 3:07

Anik Islam Abhi

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2 Comments

GMB Over a year ago

I am assuming ur missing a ";" after str+="#".. shouldn't it be str+="#";.. not that it matters, even without it; still works perfect..

Anik Islam Abhi Over a year ago

Thanks for pointing . it's just a typo . it's not a big deal in javascript though @GMB

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