PHP $_POST function not recognizing HTML form input value

Question

I can't seem to apply the $_POST function properly to retrieve the data from a simple HTML form. I'm new to PHP, so I may be overlooking something simple.

I have a form with action directing to the same page, but if the form is filled out, the value of $_POST['input_name'] will have changed, so I can trigger the php function using that condition. Is this the best way to structure this kind of action?

Here's my HTML code (thispage.php is the current/same page):

<form action="thispage.php" method="post">
  Name: <input type="text" name="userName" id="userName" />
  <input type="submit" />
</form>

Here's my PHP code from the same page:

if("" == trim($_POST['userName'])){
  echo $_POST['userName'];
}

Thanks a lot in advance!!

If the posted value equals an empty string then what exactly do you expect to see from that echo statement? — David
– David, Commented Nov 16, 2015 at 11:43
STYLE ONLY POINT: username does not have camelCase in it as it is a recognised word in the Oxford English Dictionary — Can O'Spam feels disassociated
– Can O'Spam feels disassociated, Commented Nov 16, 2015 at 11:50

Kausha Mehta · Accepted Answer · 2015-11-16 11:44:18Z

4

First remove the action from form if your server side code is in the same page. And Use the empty() or isset() functions for checking the value.

For Example:

if(!empty(trim($_POST['userName']))){
  echo $_POST['userName'];
}

if(isset(trim($_POST['userName']))){
  echo $_POST['userName'];
}

answered Nov 16, 2015 at 11:44

Kausha Mehta

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Comments

Andrius · Accepted Answer · 2015-11-16 11:41:36Z

2

if("" == trim($_POST['userName'])){
  echo $_POST['userName'];
}

This is actually checking if the value is empty and echoes it if it is.

You probably want to use !empty($_POST['userName']) to check if it's not empty and then echo it if it is not.

answered Nov 16, 2015 at 11:41

Andrius

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Comments

Apb · Accepted Answer · 2015-11-16 11:45:56Z

2

try this:

HTML code

<form action="thispage.php" method="post">
  Name: <input type="text" name="userName" id="userName" />
  <input type="submit" name="submit" />
</form>

PHP code on the same page:

if(isset($_POST['submit']))
{
    if(isset(trim($_POST['userName']))){
        echo $_POST['userName'];
    }
}

answered Nov 16, 2015 at 11:45

Apb

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Comments

Ajay Makwana · Accepted Answer · 2015-11-16 11:46:21Z

1

Try this...

if(trim($_POST['userName']) != ' '){
    echo $_POST['userName'];
}

answered Nov 16, 2015 at 11:46

Ajay Makwana

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Comments

Chirag Patel · Accepted Answer · 2019-08-08 06:46:14Z

1

you can try it:

if(isset($_POST['userName'])){
 $name = $_POST['userName'];
 echo $name;
}

answered Aug 8, 2019 at 6:46

Chirag Patel

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