I'm attempting to look for a keyword of a text file within a directory then find out the whole name of the file using Python.
Let this keyword be 'file', but this text file in the directory is called 'newfile'.
I'm trying to find out the name of the whole file in order to be able to open it.
import os
keyword = 'file'
for fname in os.listdir('directory/with/files'):
if keyword in fname:
print(fname, "has the keyword")
You could use fnmatch. From the documentation:
This example will print all file names in the current directory with the extension .txt:
import fnmatch
import os
for filename in os.listdir('.'):
if fnmatch.fnmatch(filename, '*.txt'):
print filename
From your example you would want fnmatch(filename, '*file*').
e.g:
>>> from fnmatch import fnmatch
>>> fnmatch('newfile', '*file*')
True
>>> fnmatch('newfoal', '*file*')
False
Using grep you can locate file containing the word you are looking for.
grep -r 'word' FOLDER
-r indicates grep to look for 'word' in all the files of FOLDER
