Suppose I have a string like this:
s="b a[1] something funny"
and I have these variables
b="10"
a=["1","is"]
is it possible for me to somehow replace values in the first string with values from my variables, hopefully with one function. I don't want to execute the string with eval because it contains invalid Python code.
s="b sx[1] something funny"
b="10"
sx=["1","is"]
map = {}
for i in range(0,len(sx)):
map["sx["+str(i)+"]"]=sx[i]
map['b'] = b
lis = s.split(" ")
ans = []
for i in range(0,len(lis)):
try:
ans.append(map[lis[i]])
except Exception, e:
ans.append(lis[i])
ans = " ".join(ans)
print ans
Hope this helps
You could use this kind of formatting:
s = '{b} {a} something funny'.format(b="10", a=["1","is"])
That does the work, at least on your example:
b="10"
a=["1","is"]
def protectedEval(mystr):
ret = []
for i in mystr.split():
try:
ret.append(eval(i))
except NameError:
ret.append(i)
return ' '.join(ret)
protectedEval("b a[1] something funny")
But you probably should use either .format or %.
In yet to be released Python 3.6 you can use Literal String Interpolation. For example:
>>> b = "10"
>>> a = ["1", "is"]
>>> s = f"{b} {a[1]} something funny"
>>> print(s)
10 is something funny
If you could turn your string template into a 'formattable' one, this should work:
s="{b} {a[1]} something funny"
b="10"
a=["1","is"]
print s.format(**locals())
10 is something funny
Although you should avoid locals() in favour of an esplicit dictionary:
s="{b} {a[1]} something funny"
parms = dict(
b="10",
a=["1","is"]
)
print s.format(**parms)
10 is something funny
s..format()would help :s = "{} {} something funny".format(b,s[0])