Open a .log extension file in Python

Question

I'm trying to open a .log extension file in Python but I keep encountering an IOError. I'm wondering if this has to do with the extension because clearly, the only way to get into that loop was if 'some.log' existed in the directory.

location = '/Users/username/Downloads'

for filename in os.listdir(location):
    if filename == 'some.log':
       f  = open('some.log', "r")
       print (f.read())

Traceback:

f  = open('some.log', "r")
IOError: [Errno 2] No such file or directory: 'some.log'

is some.log in the working directory? Tryopen( os.path.join(location, 'some_log')) — James
– James, Commented Nov 20, 2015 at 17:06

Wondercricket · Accepted Answer · 2015-11-20 17:06:33Z

6

When attempting to open a file in a different directory, you need to supply the absolute file path. Otherwise it attempts to open a file in the current directory.

You can use os.path.join to concatenate the location and filename

import os

location = '/Users/username/Downloads'
for filename in os.listdir(location):
    if filename == 'some.log':
       f  = open(os.path.join(location, 'some.log'), "r")
       print (f.read())

answered Nov 20, 2015 at 17:06

Wondercricket

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