Here is my current code:
for i do
sum=$(expr $sum + $i)
done
echo =$sum
Now this works, but I want it to display all of the numbers. For example, If I enter ./sum 1 2 3, I want it to display 1+2+3=6. Right now it only displays the answer. Also, is there a way I could execute the file without ./. For instance, could I use sum 1 2 3 instead of ./sum 1 2 3. I've tried chmod 700 "myfile," but that didn't seem to work.
What about this?
while (( $# > 1 )); do
printf "$1 + "
sum=$((sum + $1 ))
shift
done
echo "$1 = $((sum + $1))"
It loops through the arguments you provide and adds them into the variable $sum. For stylistic purposes I use printf and finally echo to have everything in the same line.
The usage of shift is explained here:
The
shiftbuiltin command is used to "shift" the positional parameters by the given number n or by 1, if no number is given.
$ sh script.sh 1 2 3
1 + 2 + 3 = 6
$ sh script.sh 1 2 3 4 5
1 + 2 + 3 + 4 + 5 = 15
You can use IFS and $* to join all the arguments with +:
(IFS="+"; printf '%s' "$*")
sum=0
for i; do
sum=$((sum + i))
done
printf '=%d\n' "$sum"
To run without the ./ prefix, you need to put the program in a directory that appears in your PATH. Unless this is intended for people other than you, you should create a bin directory in your home directory, then add this to your .bash_profile:
PATH=~/bin/:$PATH
so that your bin directory is added to the list of places to look for commands.
IFS="+"; echo $(($(printf '%s' "$*")))?
sum() { IFS="+"; echo $(($(printf '%s' "$*"))); } and use it this way: sum 1 2 3
IFS globally; that's why I made the original change in a subshell.Another answer:
sum=0
for i in $@
do
sum=$(($sum + $i))
done
echo $sum
sh or bash to call it then you won't need to prefix ./sh /path/to/script.sh 1 2 3 4 5. You can also add the method to your .bashrc or place the script in your PATH.Here a solution without loops:
numbers=$( printf -v str '%s+' $@; printf '%s' "${str%+}" )
sum=$(( $numbers ))
echo $numbers=$sum
the first line joins the input arguments with +, the second line calculates the sum and the third line outputs the equation
as to the second part of your question. Just put the script somewhere in your path (for example /usr/local/bin)
echo $PATH. This will give you a list of paths separated by colons (for example /bin:/usr/bin:/usr/local/bin. The default path for programs that you install yourself is /usr/local/bin.