Pulling in fields through an array

Question

I'm using a wordpress plugin names "Advanced Custom Fields". Within the admin I have a select field where multiple choices can be selected.

So for example the admin will have the following selected....

/apples-category/ : Read More on apples
/pears-category/ : Read More on pears
/oranges-category/ : Read More on oranges
/peach-category/ : Read More on peaches

The first part which is the value (/apples-category/) will be used within a hyper link. The second part which is the label (Read More on apples) will be the anchor text.

I've put the following together which outputs the following correct labels but for some reason they all have the href (value) of the very last option (/peach-category/)

Read More on apples, Read More on pears, Read More on oranges, Read More on peaches

Here's my code and apologies if it looks obvious, I've just started out coding and still need assistance :)

Hope you can assist.

 <?php
 $labels = array();
 $field = get_field_object('select_fruit');
 $values = get_field('select_fruit');
 foreach ($values as $value) {
 $labels[] = $field['choices'][ $value ];
 }

 foreach ($labels as $k=>$label){
 echo '<a href="'.$value.'" />'.strtoupper($label).'</a>'.($k ==                 count($labels) - 1 ? '' : ', ');
}?>

score 1 · Accepted Answer · 2015-11-30 11:56:32Z

1

Try this code:

<?php
 $fruit_array = array();
 $field = get_field_object('select_fruit');
 if(!empty($field['value']))
 {
     foreach ($field['value'] as $value)
     {
        $fruit_array[$value]=$field['choices'][ $value ];
     }
     $cnt=0;
     foreach ($fruit_array as $fruit_key=>$fruit_value)
     {
        echo '<a href="'.$fruit_key.'" />'.strtoupper($fruit_value).'</a>'.($cnt == count($fruit_array) - 1 ? '' : ', ');
        $cnt++;
     }
 }
?>

edited Nov 30, 2015 at 11:56

answered Nov 27, 2015 at 12:36

user4094161

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4 Comments

Billy Bragg in the UK Over a year ago

Thank you so much :) It works perfectly. I'm going to study how your code was put together so I know where I went wrong. It looks like I was missing a second foreach for the value.

Billy Bragg in the UK Over a year ago

Just one question if I may... I get the following error on this line.. foreach ($field['value'] as $value).......PHP Warning: Invalid argument supplied for foreach() in..... Any ideas how to fix the warning?

Billy Bragg in the UK Over a year ago

And also the following from the same line..... PHP Warning: Illegal offset type in

user4094161 Over a year ago

For Warning: Invalid argument supplied for foreach() in....you just need to check that $field['value'] array is not empty. I have updated the answer, please check.

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