I have a loop
for (var i=0; i < x; i++){
// ..
}
I want to wrap each 8 numbers between two characters. So my output would look something like this:
< 0 1 2 3 4 5 6 7 > < 8 9 10 11 12 13 14 15 > < 16 17 18 19 20 21 22 23 > < ...
My solution was
if(i == 0) console.info('<');
if(i == 7) console.info('>');
if(i == 8) console.info('<');
if(i == 15) ...
But this would be pretty verbose. Is it possible to make this task easier?
You can check if i falls between 7 and 8 using the % (mod) operator. x % y returns the remainder if dividing x by y. For example:
0 % 4 == 0
1 % 4 == 1
2 % 4 == 2
3 % 4 == 3
4 % 4 == 0
5 % 4 == 1
A solution using this method would look like:
var limit = 64;
console.info('< ');
for (var i = 0; i < limit; i++) {
if (i % 8 == 0 && i > 0) {
console.info('> <');
}
console.info(i, ' ');
}
console.info('>');
console.log(i, ' ') as well.
console.info()s aren't in all the optimal places, this is the best answer here so far.Sure.
var iterations = 3;
for (var i = 0; i < iterations; i++) {
console.log("<");
for (var j = i * 8; j < ( i * 8 ) + 8; j++)
console.log(j);
console.log(">");
}
Try this:
(function() {
var result = "";
var x = 25;
for (var i = 0; i < x; i++) {
if (i % 8 == 0) {
result += "> <"
}
result += " " + i + " ";
}
result += " >"
console.log(result.substring(1));
})()
console.info('<');
for (var i=0; i < x; i++){
if ((i > 0) && (i %8) == 0) {
console.info('><');
}
}
console.info('>');
Basically, what we are doing here is saying, if i divided by 8 has a remainder of 0, then add the brackets. Thus, every 8 numbers.
Hope this helps!
My suggestion,
var limit = x/8;
var chunk;
for (var i=0; i<limit; i++) {
console.log('<');
chunk = i*8;
for (var j=chunk; j<chunk+8; j++)
console.log(j);
console.log('>');
}
