How to load content from other page in index page with using url variable

Question

I am trying to lad content from page1.php, page2.php and page3.php with the help of url varibale in my index page.

Here is my index page code

<html>
<head>
</head>
<body>
<h1>Hello there></h1>
<ul>
<li><a href="index.php?page=page1.php">page 1</a>page1</li>
<li><a href="index.php?page=page2.php">page 2</a>page2</li>
<li><a href="index.php?page=page3.php">page 3</a>page3</li>
</ul>
<?php
    $page = $_GET['page'];
    $pages = array('page1', 'page2', 'page3');
    if (!empty($page)) {
        if(in_array($page,$pages)) {

            include($page);
        }
        else {
        echo 'Page not found. Return to
        <a href="index.php">index</a>';
        }
    }
    else {
        include('page1.php');
    }
?>
</body>
</html>

the index page shows undefined variable $page

$page will get you pagex.php and you are checking it with pagex in inarray what is the value in $page. — saurabh kamble
– saurabh kamble, Commented Dec 3, 2015 at 4:18
If you are going to do this method you should just do page=1 then check if 'page'.$_GET['page'].'.php' is a file — Rasclatt
– Rasclatt, Commented Dec 3, 2015 at 4:23
when you visit index.php the key 'page' is not set in your $_GET array. if you want to avoid that notice you will want to check isset($_GET['page']) before assigning it to $page — KorreyD
– KorreyD, Commented Dec 3, 2015 at 4:24

Tintu C Raju · Accepted Answer · 2015-12-03 04:19:05Z

1

you have to use array('page1.php', 'page2.php', 'page3.php'); or avoid .php extension from url aswell as array and use $page.".php" in include. Also make sure that $_GET['page']; is set

<html>
<head>
</head>
<body>
<h1>Hello there></h1>
<ul>
<li><a href="index.php?page=page1.php">page 1</a>page1</li>
<li><a href="index.php?page=page2.php">page 2</a>page2</li>
<li><a href="index.php?page=page3.php">page 3</a>page3</li>
</ul>
<?php
    $page = isset($_GET['page'])?$_GET['page']:'page1.php';
    $pages = array('page1.php', 'page2.php', 'page3.php');
    if (!empty($page)) {
        if(in_array($page,$pages)) {

            include($page);
        }
        else {
        echo 'Page not found. Return to
        <a href="index.php">index</a>';
        }
    }
    else {
        include('page1.php');
    }
?>
</body>
</html>

answered Dec 3, 2015 at 4:19

Tintu C Raju

2,7002 gold badges23 silver badges25 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Matt Oaxaca · Accepted Answer · 2015-12-03 04:11:06Z

0

I'd recommend using a routing system from a framework.

Aside from that your $_GET variable: index.php?page=page1.php is returning the string "page1.php" which doesn't exist in your $pages array. Add the .php into your $pages array and you should have it working.

Recommendations for routing systems: http://silex.sensiolabs.org/

Uses symfonys routing and request components. Will save you some headaches.

answered Dec 3, 2015 at 4:11

Matt Oaxaca

1961 silver badge10 bronze badges

3 Comments

Nishant Over a year ago

okkk. My array contains page1.php, page2.php and page3.php.It is working fine but on index.php page it still shows Notice: Undefined index: page in C:\xampp\htdocs\mynew\index.php on line 12

Matt Oaxaca Over a year ago

Php Notices can be disabled in the ini file, but the notice is being thrown because you're attempting to pull an member of an array that doesn't exist: like page4.php. I'd double check to make sure no funny business is happening in-relation to your arrays.

Matt Oaxaca Over a year ago

More information on php errors, warning, notices : pc-freak.net/blog/turn-php-notices

Parth Chavda · Accepted Answer · 2015-12-03 04:57:25Z

<html>
<head>
</head>
<body>
<h1>Hello there></h1>
<ul>

change page1.php to page1 beacuse in array there is no page1.php it's only page1.....

<li><a href="index.php?page=page1">page 1</a>page1</li>
<li><a href="index.php?page=page2">page 2</a>page2</li>
<li><a href="index.php?page=page3">page 3</a>page3</li>
</ul>
<?php

you got undefine index because first time when page load $_GET['page'] doesn't exit.you need to check wether $_GET['page'] is set or not

if(isset($_GET['page']))
{
    $page = $_GET['page'];
    $pages = array('page1', 'page2', 'page3');
    if (!empty($page)) {
        if(in_array($page,$pages)) {

here $page only contain page1,page2...else so you need to concate with ".php"

            include($page.".php");
        }
        else {
        echo 'Page not found. Return to
        <a href="index.php">index</a>';
        }
    }
    else {
        include('page1.php');
    }
}
?>
</body>
</html>

Collectives™ on Stack Overflow

How to load content from other page in index page with using url variable

3 Answers 3

Comments

3 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

3 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related