Using a loop to replace values found in one array with the same index value of a second array?

Question

I'm trying to replace links from a dynamic feed after the results are displayed on the page using JQuery.

Basically, the idea is to look for the values of ARRAY1 and replace them with the same index value of ARRAY2. For example:

ARRAY1 = ['hello','how','are','you'];
ARRAY2 = ['hi'   , 'I' ,'am' ,'ok'];

So, if the loop finds the VALUE 'hello', then replace it for 'hi', if it finds 'how' then replace it with 'I'... and so on.

so u mean to say that all the values in array1 should be replaces with array2? — Harry Bomrah
– Harry Bomrah, Commented Dec 4, 2015 at 11:02
Hi, only if they are found... and they should be replaced with the equivalent index value from the array2, if for example array1[3] doesn't exist, the loop should skip it, and when it finds array1[4] should replace it with the value of array2[4] — LEPJD
– LEPJD, Commented Dec 4, 2015 at 11:05
the idea is to replace links from an instagram feed, to make only some items go to a different link that won't be the link to the instagram post, and the array1 will be created manually, so because the feed itself will be limited to certain amount of items, and some items in between we won't want to replace the link, the some values should be skipped.... — LEPJD
– LEPJD, Commented Dec 4, 2015 at 11:09

Yeldar Kurmangaliyev · Accepted Answer · 2015-12-04 11:10:08Z

1

You can simply use replace for every item in your array.

var arr1 = ['hello','how','are','you'];
var arr2 = ['hi'   , 'I' ,'am' ,'ok'];

var str = "hello, my friend. how are you doing? Let me say it again: hello, hello, hello";

for (var i = 0; i < arr1.length; i++)
{
  while (str.indexOf(arr1[i]) > -1) 
    str = str.replace(arr1[i], arr2[i]);
}

document.body.innerText = str;

answered Dec 4, 2015 at 11:10

Yeldar Kurmangaliyev

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1 Comment

kaapa Over a year ago

It will make more sense to use object (map in this case) of "mappings" instead of the arr1 and arr2. You won't need to have all of the logic inside for loop. Eg. mappings['hello'] should return 'hi'.

Amit · Accepted Answer · 2015-12-04 11:26:12Z

1

Try something like

var result = ARRAY1.map(function (dt, i) {
  return ARRAY2[i]
});

This way you don't have to bother if array2 and array1 have different lengths. :)

answered Dec 4, 2015 at 11:26

Amit

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Comments

mjois · Accepted Answer · 2015-12-04 11:07:15Z

0

For each word in your loop:

var index = ARRAY1.indexOf(word);
if (index >= 0) {
    word = ARRAY2[index];
}

Caching the results of indexOf may help with efficiency, depending on the scale of your inputs.

answered Dec 4, 2015 at 11:07

mjois

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user1615664 · Accepted Answer · 2015-12-04 11:08:08Z

0

ARRAY1 = ['hello','how','are','you'];
ARRAY2 = ['hi'   , 'I' ,'am' ,'ok'];
value = 'hello';
if(ARRAY2[ARRAY1.indexOf(value)]>-1){
   console.log(ARRAY2[ARRAY1.indexOf(value)]);
}

answered Dec 4, 2015 at 11:08

user1615664

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Raider · Accepted Answer · 2015-12-04 11:11:52Z

0

Try this if you want to replace all

for(var i = 0; i< ARRAY2.lenght; i++){
ARRAY1[i] = ARRAY2[i];

//or
ARRAY2[i] = ARRAY1[i];
}

answered Dec 4, 2015 at 11:11

Raider

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Comments

Harry Bomrah · Accepted Answer · 2015-12-04 11:12:19Z

0

Try this.

var ARRAY1 = ['hello','how','are','you'];
var ARRAY2 = ['hi'   , 'I' ,'am' ,'ok'];
var replaceValue = function(wordToReplace){
     var index = ARRAY1.indexOf(wordToReplace);
     ARRAY1[index] = ARRAY2[index];
}
replaceValue("hello");

answered Dec 4, 2015 at 11:12

Harry Bomrah

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