JavaScript random order functions

Question

I have the following problem:

I want to call my functions func1(), func2() & func3() in a random order. But i want to be sure that every function is called!

If it's possible it also would be nice that no functions are used; just a random order of code sequences. Like this:

function xy(){

   //Call this sequence first second or third
   doSomething1

   //Call this sequence first second or third
   doSomething2

   //Call this sequence first second or third
   doSomething3

   //!! But call each sequence !!

}

Thanks in advance ;)

@NinaScholz random order call?

Sebastian Schneider
– Sebastian Schneider

2015-12-05 22:34:26 +00:00
Commented Dec 5, 2015 at 22:34 — Sebastian Schneider
– Sebastian Schneider, Commented Dec 5, 2015 at 22:34
it depends of the purpose.

Nina Scholz
– Nina Scholz

2015-12-05 22:37:54 +00:00
Commented Dec 5, 2015 at 22:37 — Nina Scholz
– Nina Scholz, Commented Dec 5, 2015 at 22:37

Tobias Baumeister · Accepted Answer · 2015-12-05 22:54:51Z

3

You could put all function names as strings into an Array, then sort this array randomly and call the functions:

var funcArr = new Array("func1", "func2", "func3");
shuffle(funcArr); //You would need a shuffle function for that. Can be easily found on the internet.

for (var i = 0; i < funcArr.length; i++)
    window[funcArr[i]]();

EDIT: If you don't want functions but lines of code to be sorted randomly, then that's not going to work. JavaScript does not have a goto command (at least not without an external API), so you can't jump between code lines. You can only mix functions, as shown above.

edited Dec 5, 2015 at 22:54

answered Dec 5, 2015 at 22:37

Tobias Baumeister

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7 Comments

Sebastian Schneider Over a year ago

Do you think there is possiblity to do this without external functions, just with code sequences? --> 3 sequences called in random order.

Tobias Baumeister Over a year ago

What do you mean by external functions? The shuffle method? And does that exclude functions like Math.random() as well? Because otherwise there is no possibility.

Sebastian Schneider Over a year ago

I have code seq1, code seq2, ... and want to call them in a random order

Tobias Baumeister Over a year ago

Yeah, but what do you mean by external functions? That idea requires some kind of randomness, and randomness can only be created by using functions such as Math.random().

Sebastian Schneider Over a year ago

I dont want to do function xy(){...}, i want to randomise the sequences in a function

|

Nina Scholz · Accepted Answer · 2015-12-05 23:07:19Z

2

You can use something like the Fisher-Yates shuffle for shuffling the functions and then call them via Array.prototype.forEach():

var a = function () { alert('a'); },
    b = function () { alert('b'); },
    c = function () { alert('c'); },
    array = [a, b, c];

array = array.map(function (a, i, o) {
    var j = (Math.random() * (o.length - i) | 0) + i,
        t = o[j];
    o[j] = a;
    return t;
});

array.forEach(function (a) { a(); });

edited Dec 5, 2015 at 23:07

answered Dec 5, 2015 at 22:56

Nina Scholz

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Comments

Jan Cássio · Accepted Answer · 2015-12-05 22:46:20Z

1

There is many ways to do that, one of the most easy way is like this:

Array.prototype.shuffle = function () {
  this.sort(function() { return 0.5 - Math.random() });
}

[func1, func2, func3].shuffle().forEach(function(func, index, array){
  func();
});

answered Dec 5, 2015 at 22:46

Jan Cássio

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