How do I get the correct result in the list of lists sorting in python [duplicate]

Question

How do I sort the list below?

My results was:

['10','11','12','7','8','9'],['1','2','3','4','5','6']]

Here's my code

lst= [['7','10','8','9','11','12'],['3','1','2','4','6','5']]

for i in lst:
    i.sort()
    print(i)

Just google how to sort list in python. ..you will find a lot of stuff about that topic — Maduro
– Maduro, Commented Dec 6, 2015 at 22:46
@BrianCain asks a perfectly reasonable question: what is wrong with the output you got? Seems to me like your were sorting strings and you got the expected output from sorting those strings. Nothing obvious worng with that. You'll have to tell us what the problem is. — DisappointedByUnaccountableMod
– DisappointedByUnaccountableMod, Commented Dec 6, 2015 at 22:48
think about it for a second, you got a list with 2 lists within it right? to access the first one you'd do lst[0] and to access the other lst[1]... I leave the rest for you. — Felipe Alarcon
– Felipe Alarcon, Commented Dec 6, 2015 at 22:52

Remi Guan · Accepted Answer · 2015-12-06 23:02:50Z

2

Use sorted(list, key=int):

lst= [['7','10','8','9','11','12'],['3','1','2','4','6','5']]

for i in lst:
    i = sorted(i, key=int)
    print(i)

edited Dec 6, 2015 at 23:02

Remi Guan

22.5k17 gold badges68 silver badges90 bronze badges

answered Dec 6, 2015 at 23:01

Meph-

6771 gold badge8 silver badges22 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Remi Guan Over a year ago

Fine, don't know that before :)

Remi Guan · Accepted Answer · 2015-12-06 22:55:43Z

1

These are string objects, for string:

'10' < '7' because `1 < 7`

I think you want:

>>> [sorted(map(int, i)) for i in lst]
[[1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12]]
>>>

Just covert them to int objects before sort.

If you need keep them in string object, covert them back or set a key:

>>> [list(map(str, i)) for i in [sorted(map(int, i)) for i in lst]]
[['7', '8', '9', '10', '11', '12'], ['1', '2', '3', '4', '5', '6']]

>>> [sorted(i, key=lambda x: int(x)) for i in lst]
[['7', '8', '9', '10', '11', '12'], ['1', '2', '3', '4', '5', '6']]

answered Dec 6, 2015 at 22:55

Remi Guan

22.5k17 gold badges68 silver badges90 bronze badges

1 Comment

python_fan Over a year ago

This is giving me: [[7, 8, 9, 10, 11, 12], [1, 2, 3, 4, 5, 6]] not [1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12] thank you

Collectives™ on Stack Overflow

How do I get the correct result in the list of lists sorting in python [duplicate]

2 Answers 2

1 Comment

1 Comment

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

1 Comment

Linked

Related