How to pass a variable to curl command in perl script?

Question

I am trying to pass a variable to curl command in Perl script. But it is failing.

But when I run the same curl command from command prompt it is working.

my $id=3;

system('curl -D- -u username:password -X PUT --data {\"fields\":{\"priority\":{\"id\":\"${id}\"}}} -H "Content-Type: application/json" -k https:request);

When I execute above Perl script I am getting error as below.

{"errorMessages":[],"errors":{"priority":"The priority selected is invalid."}}after curl command

When I run the above command from command prompt by replacing id with value it is passing.

'curl -D- -u username:password -X PUT --data {\"fields\":{\"priority\":{\"id\":\"3 \"}}} -H "Content-Type: application/json" -k https:request

Please help me here and let me know what is wrong in my code.

Hi Bobby, change your code so you store the value of the system call to the variable and print it to the error log (warn) to see the exact command you are calling. One difference i noticed is that in the working version you have added a space to the id. Maybe this is the reason? HTH George — Georg Mavridis
– Georg Mavridis, Commented Dec 15, 2015 at 7:38
my $var=qq('curl -D- -u username:password -X PUT --data {\"fields\":{\"priority\":{\"i ... ); warn $var; system($var); — Georg Mavridis
– Georg Mavridis, Commented Dec 15, 2015 at 7:39
Thanks for the response. After running with your suggestion I can see the command as: curl -D- -u username:pass -X PUT --data {"fields":{"priority":{"id":"3"}}} -H "Content-Type: application/json" -k https:website But I am getting another error as below. {"errorMessages":["Unexpected character ('f' (code 102)): was expecting double-quote to start field name\n at [Source: org.apache.catalina.connector.CoyoteInputStream@22a30637; line: 1, column: 3]"]}after curl command Thanks!! — Bobby
– Bobby, Commented Dec 15, 2015 at 7:46

Sabuj Hassan · Accepted Answer · 2015-12-15 07:50:26Z

1

You are placing the command inside the single quote. And perl takes it as it is inside single quote. As you are passing $id variable with the command, I'll suggest you to use double quote. For example

system("curl ... $id... -k https:request");
       ^ double quote                   ^

Or you can do it like this way by using concatenation.

system('curl -D- -u ...' . $id . '... -k https:request');
                          ------ concatenation

answered Dec 15, 2015 at 7:50

Sabuj Hassan

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3 Comments

Bobby Over a year ago

After adding concatenation I ma getting below error. [{"errorMessages":["Unexpected end-of-input: expected close marker for OBJECT (from [Source:org.apache.catalina.connector.CoyoteInputStream@52ba9b51; line: 1, column: 0])\n] The command I have given is: [system('curl -D- -u username:pass-X PUT --data {\"fields\":{\"priority\":{\"id\":'.${id}.'}} -H "Content-Type: application/json" -k https:request');

Sabuj Hassan Over a year ago

@Bobby your json has 3 open bracket, and 2 closing bracket. That means your json is incorrect!

Bobby Over a year ago

@Hassan ohh yeah. I have changed it but now getting new error. {"errorMessages":[],"errors":{"priority":"Could not find valid 'id' or 'name' in priority object."}}after curl command. :(

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