Unity C#, How to call a function from another script to start animation?

Question

using UnityEngine; using System.Collections;

public class ClickToMoveScript : MonoBehaviour  
{
    public string Chopping = "Chopping";

    public void PlayWoodCuttingAnim()   
    {       
        //Play Woodcutting Animation        
        gameObject.GetComponent<Animation>().CrossFade (Chopping);  
    }     
}

Heres my other Script

using UnityEngine; 
using System.Collections;

public class WoodCuttingScript: MonoBehaviour  
{
    ClickToMoveScript ClickToMove;

    void Start()
    {
        ClickToMove.PlayWoodCuttingAnim();  
    }  
}

Unity Debugger

I have already added the animation inside the animation component.

The other thing i found out is that if i call the PlayWoodCuttingAnim() function inside ClickToMove script it works fine but in the other script it dosent work.

The error console > NullReferenceException: Object reference not set to an instance of an object.

Any help would be greatly appreciated

standard way of doing this in Unity is to 1. make your ClickToMove variable public, 2. select your object with WoodCuttingScript in hierarchy in Unity, drop the object with ClickToMoveScript in the ClickToMove slot in inspector. (keep WoodCuttingScript selected all the time, do not select ClickToMoveScript) — Nika Kasradze
– Nika Kasradze, Commented Dec 23, 2015 at 13:16
I not work with Unity3d some time ago but it looks just a object reference problem. Try to do ClickToMove = new ClickToMoveScript(); before ClickToMove.PlayWoodCuttingAnim(); or attach ClickToMoveScript to the gameObject and do gameObject.GetComponent<ClickToMoveScript>().PlayWoodCuttingAnim(); instead ClickToMove.PlayWoodCuttingAnim(); — Ninita
– Ninita, Commented Dec 23, 2015 at 13:24

Hamza Hasan · Accepted Answer · 2020-07-14 11:36:56Z

9

Well, there are few common methods to do so.

Like calling method from another script you will need to get attached (to gameObject) script instance instead of simple script instance.

You can do it by,

void Start()
{
    ClickToMove = FindObjectOfType<ClickToMoveScript>();
    ClickToMove.PlayWoodCuttingAnim();  
}

edited Jul 14, 2020 at 11:36

answered Dec 23, 2015 at 13:21

Hamza Hasan

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4 Comments

Hamza Hasan Over a year ago

2nd is delegate, if you want to play with delegates, then let me know

Everts Over a year ago

That is only valid if you have only one ClickToMoveScript.

Hamza Hasan Over a year ago

Yups. if you have multiple then ClickToMoveScript[] ClickToMoveArray = FindObjectsOfType<ClickToMoveScript>(); then call foreach(ClickToMoveScript c in ClickToMoveArray ) c.PlayWoodCuttingAnim();

Suraksha Ajith Over a year ago

Thanks for the code@HamzaHasan this works like a charm :)

Tom · Accepted Answer · 2015-12-23 13:21:33Z

2

Try using .GetComponent<YourScriptName>.YourFunction().

Your function will (I believe) have to be public in order to use in another script :)

answered Dec 23, 2015 at 13:21

Tom

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Comments

Valentin · Accepted Answer · 2015-12-23 13:21:43Z

0

You should use GetComponent to get instance of another script.

    ClickToMove= gameObject.GetComponent("ClickToMoveScript") as ClickToMoveScript;
    ClickToMove.PlayWoodCuttingAnim();

answered Dec 23, 2015 at 13:21

Valentin

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Comments

score 0 · Accepted Answer · 2017-03-18 04:57:43Z

0

Here is what i use:

FindObjectOfType<Sliding_Door>().Open_Door(1);

You can also use:

Sliding_Door door = FindObjectOfType<Sliding_Door>();
door.Open_Door(1);

Here is your version

FindObjectOfType<ClickToMoveScript>().PlayWoodCuttingAnim();

or

ClickToMoveScript init = FindObjectOfType<ClickToMoveScript>();
init.PlayWoodCuttingAnim();

edited Mar 18, 2017 at 4:57

answered Mar 5, 2017 at 20:10

user5216459

Comments

Eduard Muduard Marchidan · Accepted Answer · 2015-12-23 13:13:53Z

-3

You need to create a new istance of clicktomove like ClickToMoveScript ClickToMove = new ClickToMoveScript();

answered Dec 23, 2015 at 13:13

Eduard Muduard Marchidan

1

1 Comment

Jerry Switalski Over a year ago

This is not true, you cannot instatiate MonoBehaviour.

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