how to execute multiple count query in php

Question

I executed 4 count queries from one table. but I am getting the same output from all the queries. but the actual value is different in the table.

Here is my table.

ID ||  notify_type     ||  status
__________________________________________

1  || resume_uploaded  ||    1

Here are my queries:

$notify_query1 = "select count(*) from notify where status = 1 and notify_type = 'resume_uploaded'";
$row1 = mysqli_query($db_manager->connection,$notify_query1);
$rcount = mysqli_num_rows($row1);

$notify_query2 = "select count(*) from notify where status = 1 and  notify_type = 'detail_filled'";
$row2 = mysqli_query($db_manager->connection,$notify_query2);
$dcount = mysqli_num_rows($row2);

$notify_query3 = "select count(*) from notify where status = 1 and notify_type = 'job_detailed'";
$row3 = mysqli_query($db_manager->connection,$notify_query3);
$jcount = mysqli_num_rows($row3);

$notify_query4 = "select count(*) from notify where status = 1 and notify_type = 'msg_sent'";
$row4 = mysqli_query($db_manager->connection,$notify_query4);
$mcount = mysqli_num_rows($row4);

I am getting output 1 from all the four queries: Please help me.

Don't get num_row, fetch the returned row then get the count with $row["count(*)"]; — John Pangilinan
– John Pangilinan, Commented Dec 29, 2015 at 5:37

Noman · Accepted Answer · 2015-12-29 05:43:52Z

1

Use fetch_row() instead mysqli_num_rows().

$result = $db->query("select count(*) from notify where status = 1 and notify_type = 'resume_uploaded'");
$row = $result->fetch_row();
echo 'No of count: '. $row[0];

answered Dec 29, 2015 at 5:43

Noman

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