Regex for all strings not containing a specific string

Question

I need to choose the original image in my example is a 'image1.jpg' with any extension.

image1-150x150.jpg
image1-225x300.jpg
image1-768x1024.jpg
image1.jpg

I've tried the following:

preg_grep("/-([0-9]+x[0-9])+/", $image);

How do I exclude other files and select "image1.jpg"?

thanks. it's works, but I wanted to write without PREG_GREP_INVERT. because it will be used in some cases without preg_grep — Andrei Demidow
– Andrei Demidow, Commented Jan 1, 2016 at 19:54

Josh Crozier · Accepted Answer · 2016-01-01 20:26:27Z

2

I wanted to write without PREG_GREP_INVERT, because it will be used in some cases without preg_grep

Then you could use a negative lookahead to negate strings that contain the pattern \d+x\d+:

/^((?:.(?!\d+x\d+))*\.[^.]+)$/gm

It would capture image1.jpg based on the input you provided - example here.

^ - Anchor to match the beginning of the line (since the m flag is used).
.(?!\d+x\d+))* - Match zero or more characters not followed by \d+x\d+
\.[^.]+ - Match the . character literally followed by one or more characters that are not .
$ - Anchor to match the end of the line.

answered Jan 1, 2016 at 19:58

Josh Crozier

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1 Comment

It works. Thanks for the detailed description.Thanks to all who responded. Happy New Year