Python/CSV - Method to create a CSV file with argument as file name

Question

I want to create empty csv files (that will later be used for something else) with its name based on the method's arguments. It will be something like this:

def create_empty_csvs(*string_csv_names):
    for i in stringcsv_names:
        --> create empty csv file with argument name

So, if I call this:

create_empty_csvs('John','Mark','Daniel')

It would return me three different empty csv files, named 'John.csv', 'Mark.csv' and 'Daniel.csv'.

Any idea how could I do that?

oxnz · Accepted Answer · 2016-01-04 03:03:18Z

1

def create_empty_csvs(*stringcsv_names):
    for i in stringcsv_names:
        with open(i + '.csv', 'w') as f:
            pass

for more information, see python doc for open.

edited Jan 4, 2016 at 3:03

answered Jan 4, 2016 at 2:55

oxnz

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