Tried searching in the Java String API with no answer.
I am trying to create Java strings with a specified size. I noticed that Java Strings do not end in the null character (\0). Basically, I would like to be able to create strings such as:
String myString = new String("Charles", 32);
where myString will contain "Charles <-- 24 spaces --> \0"
There is no such method that can achieve what I have above. Should I just rely on creating my own function to do so?
Thanks
String myString = String.format("%1$-" + 32 + "s", "Charles");
Strings in Java are immutable. If you want those extra spaces at the end, you're simply going to have to create a string that contains those spaces.
Yeah, there probably isn't a built in function for that. You could pad the string to the required length using String.format() and then append a \0 to the end of it - that should do what you want fairly easily.
If you want to be able to work with fixed size strings in a mutable way, you could also write your own wrapper that encapsulates a presized char[], e.g.
public class MyString()
private char[] values;
public MyString(int size)
{
values=new char[size];
}
... methods to set, get
public String toString() { return new String(values);}
}
I would you one of the formatting options provided by Java to accomplish that.
For example implement your own java.text.Format implementation.
Another possibility would be to use a StringBuffer/StringBuilder with the specified capacity and initialize it with spaces and the \0. Then you can fiddle with the char positions when writing/modifying the text.
[]afterString, although you can usechar[]similarly toString(still doesn't require a NUL terminator).myStringas an array ofStrings, but then you assign a singleStringobject to it.