C# read stream get WebException

Question

I'm trying to open a connection to a server and get the response body, which is an image. I want to save it to Image, and later display it in the PictureBox. Here is my code:

try
    {
        var response = WebRequest.Create(String.Format(url + "?t=webwx&_={0}", timestamp));
        var stream = response.GetRequestStream();
        Image image = Image.FromStream(stream);
        qe_img.Image = image;
        qe_img.Height = image.Height;
        qe_img.Width = image.Width;
     } catch (Exception e)
     {
        Console.WriteLine(e);
     }

I get:

Exception thrown: 'System.Net.ProtocolViolationException' in System.dll
System.Net.ProtocolViolationException: Cannot send a content-body with this verb-type.
   at System.Net.HttpWebRequest.CheckProtocol(Boolean onRequestStream)
   at System.Net.HttpWebRequest.GetRequestStream(TransportContext& context)
   at System.Net.HttpWebRequest.GetRequestStream()
   at WindowsFormsApplication1.Form1.showQRImage() in c:\users\morgan\documents\visual studio 2015\Projects\WindowsFormsApplication1\WindowsFormsApplication1\Form1.cs:line 70

But I always get a WebException. I'm new to C#, I wonder what is wrong here. Thanks.

Wrap your code in a try--catch block and paste the exception here. And also instead of using response.ResponseStream you need to call response.GetResponseStream() — qamar
– qamar, Commented Jan 6, 2016 at 6:06
Try getting Http code from exception example:stackoverflow.com/questions/3614034/… — elrado
– elrado, Commented Jan 6, 2016 at 6:09
Try putting url from your Create() method into a IE and see if it works manually. I suspect the request is returning more than just the image. You can vailidate this by looking at the webpage returned in the IE by using menu : Source. You will need to find the tag that contains the image and extract the image from the html returned results. — jdweng
– jdweng, Commented Jan 6, 2016 at 6:36
I think you url missing something or inalid. Can you paste the value of Url variable here? — qamar
– qamar, Commented Jan 6, 2016 at 8:16

santosh singh · Accepted Answer · 2016-01-06 06:33:08Z

2

Try this

 try
            {
                var request = WebRequest.Create(String.Format(url + "?t=webwx&_={0}", timestamp));

                using (WebResponse response = request.GetResponse())
                {
                    using (Stream stream = response.GetResponseStream())
                    {
                        Image image = Image.FromStream(stream);
                        qe_img.Image = image;
                        qe_img.Height = image.Height;
                        qe_img.Width = image.Width;


                    }
                }

            }
            catch (Exception e)
            {
                Console.WriteLine(e);
            }

answered Jan 6, 2016 at 6:33

santosh singh

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