PHPQuery - get all links of contains specific url page

Question

I am trying to get all links of contains specific url page on a given page using PHPQuery. I am using the PHP support syntax of PHPQuery.

include_once 'phpQuery.php';
$url = 'http://www.phonearena.com/phones/manufacturer/';
$doc = phpQuery::newDocumentFile($url);

$urls = $doc['a'];

foreach ($urls as $url) {
    echo pq($url)->attr('href') . '<br>';
}

The code above works . But it shows all the links I want to show only those containing "/phones/manufacturer/". I tried this but it shows nothing:

include_once 'phpQuery.php';
$url = 'http://www.phonearena.com/phones/manufacturer/';
$doc = phpQuery::newDocumentFile($url);

$urls = $doc['a'];

foreach ($urls as $url) {
    echo pq($url)->attr('href:contains("/phones/manufacturer/")') . '<br>';
}

msvairam · Accepted Answer · 2016-01-06 10:26:29Z

4

Use below coding get all urls from that site,

        $doc = new DOMDocument();
                @$doc->loadHTML(file_get_contents('http://www.phonearena.com/phones/manufacturer/'));

                $ahreftags = $doc->getElementsByTagName('a');

                    foreach ($ahreftags as $tag) {
                        echo "<br/>";
                        echo $tag->getAttribute('href');
                        echo "<br/>";
                    }


exit;

answered Jan 6, 2016 at 10:26

msvairam

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Comments

BomAle · Accepted Answer · 2016-05-23 17:07:39Z

3

Try this, a little italian guide, jquery documentation

include_once 'phpQuery.php';
$url = 'http://www.phonearena.com/phones/manufacturer/';
$doc = phpQuery::newDocumentFile($url);

$urls = $doc['a[href*="/phones/manufacturer/"]'];

foreach ($urls as $url) {
    echo pq($url)->attr('href') . '<br>';
}

edited May 23, 2016 at 17:07

answered May 20, 2016 at 23:27

BomAle

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