How to create a floor function with a "step" argument

Question

I would like to create a function floor(number, step), which acts like :

floor(0, 1) = 0
floor(1, 1) = 1
floor(1, 2) = 0
floor(5, 2) = 4
floor(.8, .25) = .75

What is the better way to do something like that ?

Thanks.

Is the step always going to be a power of two, as in your examples? — Stephen Canon
– Stephen Canon, Commented Aug 12, 2010 at 22:51

x4u · Accepted Answer · 2010-08-12 22:51:46Z

6

You could do something like floor( val / step ) * step

answered Aug 12, 2010 at 22:51

x4u

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Comments

President James K. Polk · Accepted Answer · 2010-08-13 21:11:20Z

2

what you want is basically the same as

step * (x // step)

isn't ?

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answered Aug 12, 2010 at 22:56

mykhal

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Vatine · Accepted Answer · 2010-08-13 08:26:08Z

1

Something along the lines of the code below ought to do the job.

def stepped_floor (n, step=1):
    return n - (n % step)

answered Aug 13, 2010 at 8:26

Vatine

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