array_push key=>value , how can do it?

Question

I want to push key and value in array , but I can't

$con = mysqli_connect('localhost','root','','wp') or die (mysqli_error('Error:'));

$query = mysqli_query($con,'set names utf8')or die (mysql_error());
$qy = mysqli_query($con,"SELECT ID,post_title FROM wp_posts WHERE post_type='page' AND post_status='publish'")or die (mysql_error());
$arr = array();
while ($row = mysqli_fetch_array($qy)){
$id = "?page_id=".$row['ID'];
$title = $row['post_title'];
$arr[] = $id . "=>" . $title;
array_push($arr, "$id" => "$title");  
}

plz help me ..

thanks ^_^

possible duplicate of Using array_push() to add elements to an array in the form of 'key => object' — Mark Elliot
– Mark Elliot, Commented Jan 23, 2011 at 4:50

NullUserException · Accepted Answer · 2010-08-14 01:15:33Z

2

Here's what I would do instead:

$arr = array();
while ($row = mysqli_fetch_assoc($qy)){
    $id = $row['ID'];
    $arr[$id] = $row['post_title'];
}

And then when you need to print them:

foreach ($arr as $id => $title) {
    echo "?page_id={$id}'>{$title}</a>";
    // or whatever, depends on how you want to print it
}

Don't store unnecessary information (ie: ?page_id=) in arrays.

answered Aug 14, 2010 at 1:15

NullUserException

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Borealid · Accepted Answer · 2010-08-14 01:14:07Z

2

Do you want to do $arr[$id] = $title? Or do you want this:

if (!isSet($arr[$id])) {
    $arr[$id] = array();
}
$arr[$id][] = $title;

The former will make it so that $arr contains $id=>$title. The latter will make it so that $arr contains $id=>array($title1,$title2,$title3) etc if there are multiples.

answered Aug 14, 2010 at 1:14

Borealid

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2 Comments

AboSami Over a year ago

thank you very much , the result is fail .. this is the result $My_links = array('2' => 'Array' ,'4' => 'Array' ,'6' => 'Array' ,'9' => 'Array' ,'11' => 'Array' ,'13' => 'Array' ,'45' => 'Array' );

Borealid Over a year ago

@AboSami: Yes, if you use the second bit of code, that should be the result. If you use just $arr[$id] = $title, it will not, but your IDs had better be unique!

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