I'm struggling with some generics. The following is my setup:
interface I<T> { }
[...]
void Add<T>(T obj) where T : I<??> { }
How can I ensure that T in the Add method implements I?
2 Answers
The following signature will allow Add to take any T that implements I<> with any type parameters.
void Add<T,S>(T obj) where T : I<S> {
}
The downside of using this method signature is that type inference doesn't kick in and you have to specify all the type parameters, which looks downright silly:
blah.Add<I<int>, int>(iInstance);
A much simpler approach is to use the below signature:
void Add<T>(I<T> obj) {
}
1 Comment
Jon List
void Add<T>(I<T> obj) did it. Thanks!You need to pass the T parameter to add also.
void Add<TI, TAny>(TI obj) where TI : I<TAny>
1 Comment
Joe White
TI is a generic parameter, not a generic itself, so you can't do TI<TAny>. Shouldn't your parameter just be TI? And your constraint should be where T : I<TAny>.
Addis NOT part of the interfaceIbut a method on a different class