How to extract particular xml part from the given xml using XSLT

Question

I need extract <C></C>, by passing a parameter to the xslt like below

<C>
<D></D>
<D></D>
</C>

from the below XML using xslt.

<A>
<B/>
<C>
<D></D>
<D></D>
</C>
<E><D></D></E>
</A>

If I able to set the value for the element as "C", how I able to perform the above operation. My current xslt template like below.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
   <!-- Identity transform -->
   <xsl:template match="@* | node()">
      <xsl:copy>
         <xsl:apply-templates select="@* | node()" />
      </xsl:copy>
   </xsl:template>
   <xsl:param name="element" />
   <xsl:template match="/">
      <$element>
         <xsl:processing-instruction name="xml-multiple">
            <xsl:value-of select="local-name(//D)" />
         </xsl:processing-instruction>
         <xsl:copy-of select="/A/$element/D" />
      </$element>
   </xsl:template>
</xsl:stylesheet>

thx a lot Potame its worked for me. Could you tell me is this possible? <xsl:if test="$element = 'C'">$element ="E"</xsl:if> to get effected <E></E> tags — Uditha
– Uditha, Commented Jan 22, 2016 at 11:44

potame · Accepted Answer · 2016-01-22 07:48:42Z

It's not possible to enter an element name as a parameter and use it directly in the XPath for the selects.

However you could refactor your stylesheet this way:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
   <!-- Identity transform -->
   <xsl:template match="@* | node()">
      <xsl:copy>
         <xsl:apply-templates select="@* | node()" />
      </xsl:copy>
   </xsl:template>
   <xsl:param name="element" select="'C'"/>
   <xsl:template match="/">
      <xsl:element name="{$element}">

         <xsl:processing-instruction name="xml-multiple">
            <xsl:value-of select="local-name(//D)" />
         </xsl:processing-instruction>

         <xsl:copy-of select="/A/*[name() = $element]/D" />
      </xsl:element>
   </xsl:template>
</xsl:stylesheet>

The result obtained :

<?xml version="1.0" encoding="UTF-8"?>
<C>
  <?xml-multiple D?>
  <D/><D/>
</C>

corresponds to the desired output.

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