Is there a command to output only part of a command result in Linux?

Question

My question is, when we type a command with grep in terminal we get output along with the title:

For example:

lscpu | grep MHz

Will output:

CPU MHz:               1216.851

But what if I only want:

1216.851

As the output? Is there any other command to perform this task?

In addition to awk, also see cut and sed.

user2864740
– user2864740

2016-01-24 08:01:05 +00:00
Commented Jan 24, 2016 at 8:01 — user2864740
– user2864740, Commented Jan 24, 2016 at 8:01

Will · Accepted Answer · 2016-01-28 21:52:48Z

6

While there are other ways, the most straightforward would probably be awk:

$ lscpu | grep MHz | awk '{print $3}'
2494.038

Or:

$ lscpu | grep MHz | awk '{print $NF}'
2494.038

$3 represents the third field in the output (separated by any amount of whitespace). $NF represents the LAST field in the output, no matter how many fields there are.

You can also skip grep entirely and just do it all with awk:

$ lscpu | awk '/MHz/ { print $NF; exit }'
2494.038

As @glenn jackman pointed out, GNU grep can also do this:

lscpu | grep --color=never -oP 'MHz:\s+\K.*'

But the other examples above are POSIX-friendly (although systems that have lscpu probably also have GNU grep).

edited Jan 28, 2016 at 21:52

answered Jan 24, 2016 at 7:50

Will

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1 Comment

glenn jackman Over a year ago

Or, if you have GNU grep and you like PCRE regexes: lscpu | grep -oP 'MHz:\s+\K.*'

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