Why outputs in PHP and JAVA not equal

Question

import java.math.BigInteger;
import java.security.MessageDigest;
import java.security.NoSuchAlgorithmException;

public class Main {
    public static void main(String[] args) {
        String xmlRequest = " <request><merchant_id>46</merchant_id><order_id>33</order_id><amount>3</amount><description>hehe</description></request>";
        String result = encode(xmlRequest);
        String lol = "lol";
        String lolResult = encode(lol);
        System.out.println(result);
        System.out.println(lolResult);
    }

    public static String encode(String toEncode) {
        String hashStr = null;

        try {
            MessageDigest md = MessageDigest.getInstance("SHA-1");
            md.update(toEncode.getBytes());
            BigInteger hash = new BigInteger(1, md.digest());
            hashStr = hash.toString(16);
        } catch (NoSuchAlgorithmException e) {
            e.printStackTrace();
        }
        return hashStr;
    }
}

Output is:

aa4c157df0d6e95c395f2376fca94c7efa35c05d

403926033d001b5279df37cbbe5287b7c7c267fa

<?
$xml='<request><merchant_id>46</merchant_id><order_id>33</order_id><amount>3</amount><description>hehe</description></request>';
$x = sha1($xml);
echo $x;
echo  sha1("lol");
?>

Output is:

d3cfa6c8ee0f7f12d28b782ac1eb45b777792e3a

403926033d001b5279df37cbbe5287b7c7c267fa

So, why string "lol" is equals and string of xml code is not?

Vasfed · Accepted Answer · 2016-01-24 11:16:28Z

3

You have an extra space - in the beginning of your java version in comparison to php, so it's not the same string

answered Jan 24, 2016 at 11:16

Vasfed

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1 Comment

alexandr gaiduchok Over a year ago

ok, next issue: String ss = Base64.encodeBase64URLSafeString(xmlRequest.getBytes()); give me PHJlcXVlc3Q-PG1lcmNoYW50X2lkPjQ2PC9tZXJjaGFudF9pZD48b3JkZXJfaWQ-MzM8L29yZGVyX2lkPjxhbW91bnQ-MzwvYW1vdW50PjxkZXNjcmlwdGlvbj5oZWhlPC9kZXNjcmlwdGlvbj48L3JlcXVlc3Q- on PHP instead of - it have +

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