PHP display images if $value = $string?

Question

I need to know if there's a quickest and efficient way to display one or more images if $value == $string

For example: I have an cell which only contains 3 single string: 'r o g', if user put ro it will output <img src="red.gif"> and <img src="orange.gif"> So it could be random if user insert gr then it will display <img src="green.gif"> and <img src="red.gif">

Right now I can only think something like...

<?php $red = "<img src="red.gif">";
$orange = "<img src="orange.gif">";
if( $cell1 == $red ){ echo $red;}
if( $cell1 == $red && $orange ){ echo $orange.$red;}
etc...

This method might works but has to provide too many possibility and I believe there's a shorter and efficient to do that, but I haven't got any idea because still I'm learning PHP

Simply don't concatenate your output and have 3 if statements, one for each color. if (strpos($cell1, "r") !== false) { echo "<img src=\"red.gif\">"; } etc... — Typel
– Typel, Commented Jan 26, 2016 at 22:10

Dave Chen · Accepted Answer · 2016-01-26 22:14:30Z

2

How about this approach?

<?php

//define all your images here
$images = [
    'r' => 'red.png',
    'g' => 'green.png',
    'b' => 'blue.png',
    'y' => 'yellow.png',
    'o' => 'orange.png'
];

function output($input, $images) {
    $parts = str_split($input);
    foreach ($parts as $part) {
        if (isset($images[$part]))
            echo '<img src="' . $images[$part] . '">';
    }
}

echo "rgb: \n";
output('rgb', $images);

echo "\n\nyor: \n";
output('yor', $images);

echo "\n\nxxy: \n";
output('xxy', $images);

Output:

rgb: 
<img src="red.png"><img src="green.png"><img src="blue.png">

yor: 
<img src="yellow.png"><img src="orange.png"><img src="red.png">

xxy: 
<img src="yellow.png">

answered Jan 26, 2016 at 22:14

Dave Chen

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1 Comment

meda Over a year ago

this is clean I like it

meda · Accepted Answer · 2016-01-26 22:13:05Z

1

Try this approach:

for( $i = 0; $i <= strlen( $cell1 ); $i++ ) {
    $char = substr( $cell1, $i, 1 );
    switch ($char) {
        case "r":
            echo '<img src="red.gif">';
            break;
        case "o":
            echo '<img src="orange.gif">';
            break;
        case "g":
            echo '<img src="green.gif">';
            break;
        default:
            break;
    }
}

answered Jan 26, 2016 at 22:13

meda

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Comments

Pradeep Sambandam · Accepted Answer · 2016-01-26 22:23:26Z

1

Here is the code that shows an example for 3 character inputs. $string can be the posted value.

$r = '<img src="red.gif">';
$y = '<img src="yellow.gif">';
$o = '<img src="orange.gif">';
$g = '<img src="green.gif">';
$string = 'ryo';
$length = strlen($string);

for ($i=0; $i<$length; $i++) {
    echo ${''.$string[$i]};
}

edited Jan 26, 2016 at 22:23

answered Jan 26, 2016 at 22:14

Pradeep Sambandam

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1 Comment

meda Over a year ago

I dont think you need to check the length, if its 0 then there won't be any iteration

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