How do you get the file stream of an uploaded image (IFormFile) and resize it?
public ActionResult Upload(IFormFile file)
{
using (var reader = new StreamReader(file.OpenReadStream()))
{
var fileContent = reader.ReadToEnd();
var parsedContentDisposition = ContentDispositionHeaderValue.Parse(file.ContentDisposition);
//scale image here?
}
}
You can use IFormFile.OpenReadStream() to get the stream, and then just insert the stream into an Image. For this instance I scaled it to 1024x768.
Image image = Image.FromStream(file.OpenReadStream(), true, true);
var newImage = new Bitmap(1024, 768);
using (var g = Graphics.FromImage(newImage))
{
g.DrawImage(image , 0, 0, 1024, 768);
}
You can then use newImage to save or do whatever you want with.
Install from nuget : Install-Package SixLabors.ImageSharp
[HttpPost]
public IActionResult Upload(IFormFile file)
{
//Better use extension method
string fileName;
string customRoot = "wwwroot\\Upload\\";
Directory.CreateDirectory(customRoot);
var path = Path.Combine(Directory.GetCurrentDirectory(), customRoot,fileName);
using var image = Image.Load(file.OpenReadStream());
//100: height
//100: width
image.Mutate(x => x.Resize(100, 100));
image.Save(path);
return Ok();
}
for more information : https://blog.elmah.io/upload-and-resize-an-image-with-asp-net-core-and-imagesharp/
Very helpful. Thank you so much. This aspect saved me from out of memory exception.I want to make a contribution, if you are using IFormFile interface, then "file" refers to your IFormFile in the code.
This is IFormFile property of my Entity
[NotMapped]
public IFormFile MyImage1 { set; get; }
And this is how i use it
Image image = Image.FromStream(model.MyImage1.OpenReadStream(), true, true);
