How to call json from php

Question

I have written a php code that should print the response of a json call. But I am getting NULL output. I have checked my json call is working fine from a restclient.

Here is my code

<?php

    $username = "user";
    $password = "password";

    $postData = array(
            'username' => $username,
            'password' => $password,
            'msisdn' => "111111111"
            );

    $ch = curl_init('http://ip:<port>/xxx/yyy/zzz');

    curl_setopt_array($ch, array(
    CURLOPT_POST => TRUE,
    CURLOPT_RETURNTRANSFER => TRUE,
    CURLOPT_HTTPHEADER => array(
        'Content-Type: application/json'
    ),
    CURLOPT_POSTFIELDS => json_encode($postData)
    ));

    // Send the request
    $response = curl_exec($ch);

    // Check for errors
    if($response === FALSE){
    die(curl_error($ch));
    }

    // Decode the response
    $responseData = json_decode($response, TRUE);

    // Print the date from the response
    echo $responseData['published'];

    var_dump($responseData);

    ?>

Thanks in advance.

var_dump($response) and see what response you are getting. — Sougata Bose
– Sougata Bose, Commented Jan 28, 2016 at 10:58
have you checked, if your $response actually contains JSON-code, and if so, if it is valid? — Franz Gleichmann
– Franz Gleichmann, Commented Jan 28, 2016 at 10:58
var_dump($response) is giving HTTP Status 500 with following exception - javax.servlet.ServletException: org.codehaus.jackson.map.exc.UnrecognizedPropertyException: Unrecognized field "username" — parsa
– parsa, Commented Jan 28, 2016 at 11:33
@Pemapmodder print_r(json_last_error()); gave 4 as output which is a syntax error right? — parsa
– parsa, Commented Jan 28, 2016 at 11:43

cn0047 · Accepted Answer · 2016-01-28 11:15:14Z

1

Try:

$responseData = json_decode($response, true);
if (json_last_error() !== JSON_ERROR_NONE) {
    throw new \RuntimeException('Invalid JSON.');
}

answered Jan 28, 2016 at 11:15

cn0047

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2 Comments

parsa Over a year ago

i got Stack trace: #0 {main} thrown in exception

cn0047 Over a year ago

It mean that you don't receive json, or not valid json.

parsa · Accepted Answer · 2016-02-07 05:14:34Z

okay so i have solved my problem and re-wrote the code. I was actually not providing the correct form of username and password in the json fields which is really a silly mistake. I am giving my updated code here `

$data = array("user" => "$username", "pass" => "$password", "msisdn" => "$msisdn");
$data_string = json_encode($data);

$ch = curl_init('http://ip:port/call_center/account/general');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/json',
'Content-Length: ' . strlen($data_string))
);
curl_setopt($ch, CURLOPT_TIMEOUT, 5);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 5);

//execute post
$result = curl_exec($ch);

//close connection
curl_close($ch);

echo $result;


?>`

Thanks everyone.

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