Trying to do something simple, but not sure what I am doing wrong.
I simply want to call a function with number arguments and push those numbers into a new array...
function someFunction(n){
var newArray = new Array(n);
for(var i=0; i < n.length; i++){
newArray += n[i];
}
return newArray;
}
console.log(someFunction(3,5,4,5));Here is bin
This will get those numbers into the array for you. And it will do it for unlimited numbers supplied: https://jsfiddle.net/a9umss9a/3/
function someFunction(){
var newArray = [];
for(var i=0; i < arguments.length; i++){
newArray.push(arguments[i]);
}
return newArray;
}
console.log(someFunction(3,5,4,5));
console.log(someFunction(3,5,4,5,100,200,300,400,500));
n if you're not using it? Why use the Array constructor instead of var newArray = []?
You can do this as a one-liner:
function toArray() {
return [].slice.call(arguments);
}
Here's the breakdown of issues in your code.
function someFunction(n){ // this captures the FIRST argument as n
var newArray = new Array(n); // this creates a new Array of length n (in your case, 3, which is not accurate
for(var i=0; i < n.length; i++){ // n is a number and has no length property
newArray += n[i]; // newArray is an array, so you must push to it; the + operator makes no sense
}
return newArray;
}
someFunction requires 1 input of type array, not 4 inputs:
function someFunction(n){
var newArray = [];
for(var i=0; i < n.length; i++){
newArray.push(n[i]);
}
return newArray;
}
console.log(someFunction([3,5,4,5]));
function someFunction(n){ return n; } and get the same thing. The OP wanted this format: someFunction(3,5,4,5).A solution with direct building of an array.
function someFunction() {
return Array.apply(null, arguments);
}
document.write('<pre>' + JSON.stringify(someFunction(3, 5, 4, 5), 0, 4) + '</pre>');
