How to handle if statement along with and operator in python?

Question

if instanceType == instance_type and operatingSystem == operating_system and tenancy == tenancy_db:
    sku_list.append(key)

In this if statement these variables, instanceType, operatingSystem and tenancy, are user input, how to handle not to check if any user input is None.

e.g. if instanceType is None, i would like to check

if operatingSystem == operating_system and tenancy == tenancy_db:
    sku_list.append(key)

e.g. if operatingSystem is None, i would like to check

if instanceType == instance_type and tenancy == tenancy_db:
    sku_list.append(key)

e.g. if both tenancy and instanceType is None, I would like to check:

if operatingSystem == operating_system:
    sku_list.append(key)

Simliarly, it depends on whether user input in None or something else, is there any other way to do this, or i have to implement nested if else?

fjarri · Accepted Answer · 2016-02-07 05:28:29Z

2

One way is to declare a helper function:

equal_or_none = lambda x, y: x is None or x == y
if (
        equal_or_none(instanceType, instance_type) 
        and equal_or_none(operatingSystem, operating_system)
        and equal_or_none(tenancy, tenancy_db)):
    sku_list.append(key)

answered Feb 7, 2016 at 5:28

fjarri

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Riaz · Accepted Answer · 2016-02-07 05:42:07Z

1

You can also use the or operator which will treat None as false:

if (instanceType or instance_type) == instance_type and \
   (operatingSystem or operating_system) == operating_system and \
   (tenancy or tenancy_db) == tenancy_db:
    sku_list.append(key)

answered Feb 7, 2016 at 5:42

Riaz

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