Is there anyway that I can calculate the number of elements in this array?

Question

#include <iostream>
#include <string>
#include <time.h>

using namespace std;

int main(){
    srand (time( NULL));
     const char* words[] = {"Sunday", "Monday", "Tuesday", "Wedensday", "Thursday", "Friday", "Saturday"};


    int Randnum = rand() % 6;
    cout << words[Randnum] << endl;


}

So basically what I want to do is that instead of having that int Randnum = rand() % 6 ;, I want to have a variable that changes with the array. something like int Randnum rand() % totalwords;. I tried using sizeof(words but that would only work if I know how many bytes each word took. Is there any way you guys can think of that would let me count each word as 1 item so when the array grows the random number range does too?

Yuchen · Accepted Answer · 2016-02-11 03:33:59Z

5

Use this:

sizeof(words)/sizeof(words[0])

which will give you 7.

And int Randnum = rand() % 7 give you a random number between 0 and 6 and words[Randnum] is a random day in the week.

answered Feb 11, 2016 at 3:33

Yuchen

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Ed Heal · Accepted Answer · 2016-02-11 03:34:07Z

0

Try

sizeof(words)/sizeof(char *)

As the entries in words are char * and the total size of words will be the number of bytes to store the 7 character pointers

answered Feb 11, 2016 at 3:34

Ed Heal

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