FROM input type="date" value TO a Php variable

Question

I want to "save" the value of into a php variable, so if in the "datebox" there is something like 11/02/2016, I want to save this value on $date, then I can do echo $date; and see again 11/02/2016. the datepicker is important

I tried on two ways:

1.

<head>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
    <!-- Today date -->
    <input type="date" name="today" value="<?php echo date("Y-m-d");?>">
</form>
</body>

<?php
    $date = date('Y-m-d', strtotime($_POST['today']));
    echo "Today is $date";
?>

This output: Today is 1970-01-01

2.

<head>
<script>
function myFunction() {
    var date = document.getElementById("today").value;
    document.getElementById("here").innerHTML = date;
}
</script>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
    <input type="date" name="today" value="<?php echo date("Y-m-d");?>">
    <input type="hidden" id="here" name="this">
</form>
</body>

<?php

    $data = $_POST['this']));
    echo "Today is $data";

?>

This output: Today is

Can anybody help me please?

Thanks in advance.

RTFM: php.net/date You didn't specify the second argument, so by default date() will use time(), which means you're generating a "now" date, always. — Marc B
– Marc B, Commented Feb 11, 2016 at 15:39
@BesjanVeizi What do you want to achieve? Do you want to format your date in dd/mm/yy or do you want the date to always be today? — Panda
– Panda, Commented Feb 11, 2016 at 15:44
I want that every date I choose can be saved in a php format — Besjan Veizi
– Besjan Veizi, Commented Feb 11, 2016 at 15:47

Syed Muneeb Ul Hasan · Accepted Answer · 2016-09-20 16:09:07Z

1

Submit Element is missing from your form which means form is not processing anything.So put submit button to process the form.Try this code.

<head>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<input type="date" name="today" value="<?php echo date("Y-m-d");?>">
<input type="submit" name="a">
</form>
</body>
if(isset($_POST['a']))
{
  $date = date('Y-m-d', strtotime($_POST['today']));
  echo "Today is $date";
}

answered Sep 20, 2016 at 16:09

Syed Muneeb Ul Hasan

2312 silver badges4 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Michael Ryan Soileau · Accepted Answer · 2016-02-12 15:24:30Z

You don't have a submit element, and you have a coercion to null / 0 in your output. The result of the first is that you never submit anything. So your form doesn't actually process anything, a form does nothing until it's actually submitted.

Your second error results in the code always outputting the Unix Epoch, which is what a timestamp with an int result of 0 is. You need to turn on your errors for whatever server you're using. Turning off errors or suppressing them seems like a good idea, but it causes a host of easy-to-fix problems to remain undiagnosed.

This code should work on PHP 5.4 and above.

<?php
     $self = isset($_SERVER['PHP_SELF']) ? $_SERVER['PHP_SELF'] : '#';
     $now = date("Y-m-d");
     $today = isset($_POST['today']) ? $_POST['today'] : (new DateTime)->format('Y-m-d');
     $date = date('Y-m-d', strtotime($today));
     $formattedResult = "Today is $date";
?>
    <form action="<?= $self; ?>" method="POST">

    <input type="date" name="today" value="<?= $today;?>">
    <button type='submit' >
        You must submit the form to process it
        </button>
</form>
<?= $formattedResult;?>
</body>

Matt · Accepted Answer · 2016-02-12 18:15:50Z

0

Using the built in function DateTime you can do

date_default_timezone_set("Europe/London"); //Set your timezone
$dateNow = new DateTime;

echo $dateNow->format('d/m/Y'); // Will echo 11/02/2016

http://php.net/manual/en/timezones.php for a list of supported timezones

EDIT: Including your HTML:

<?php 
    date_default_timezone_set("Europe/London"); //Set your timezone
    $date = new DateTime;
?>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
    <!-- today date-->
    <input type="date" name="today" value="<?php echo $date->format('Y-m-d'); ?>">
    <input type="submit" name="test" value="test">
</form>

Then later on:

<?php
    $datePOST = new DateTime($_POST['today']);
    echo $datePOST->format('d/m/Y');
?>

I hope this is what you were looking for.

edited Feb 12, 2016 at 18:15

answered Feb 11, 2016 at 15:46

Matt

1,7573 gold badges13 silver badges26 bronze badges

2 Comments

Besjan Veizi Over a year ago

I tried your code and it works only for the actual date (the last echo prints only the date of today). When I change date on the datapicker the echo doesn't update...any idea to update the output string?

Matt Over a year ago

I added the code, with a submit button on my website : themooliecommunity.com/Solo/test.php Can you check if that is what you need? I have also update the code to include the submit button

Collectives™ on Stack Overflow

FROM input type="date" value TO a Php variable

3 Answers 3

Comments

Comments

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related