Python remove one worded strings from list

Question

words = [['hey', 'hey you'], ['ok', 'ok no', 'boy', 'hey ma']]

I have a list of lists containing strings. I understand how to remove specific elements from a list, but not how to remove those that are only one word. My desired output would be:

final = [['hey you'], ['ok no', 'hey ma']]

What I'm trying but I think it's totally wrong....

remove = [' ']
check_list = []

for i in words:
    tmp = []
    for v in i:
        a = v.split()
        j = ' '.join([i for i in a if i not in remove])
        tmp.append(j)

    check_list.append(tmp)
print check_list

"I think it's totally wrong" - does it work? Have you tested it? — jonrsharpe
– jonrsharpe, Commented Feb 18, 2016 at 14:10
yes, ive tested it, but check_list outputs the same as words — user47467
– user47467, Commented Feb 18, 2016 at 14:11
Then read the link. Cut your code down and give example input with expected and actual output, so others don't have to comb through it. — jonrsharpe
– jonrsharpe, Commented Feb 18, 2016 at 14:14

Julien Spronck · Accepted Answer · 2016-02-18 14:21:03Z

5

You can do:

words = [['hey', 'hey you'], ['ok', 'ok no', 'boy', 'hey ma']]
final = [[x for x in sub if ' ' in x.strip()] for sub in words]
# [['hey you'], ['ok no', 'hey ma']]

where I simply search for spaces in all strings.

edited Feb 18, 2016 at 14:21

answered Feb 18, 2016 at 14:16

Julien Spronck

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1 Comment

Julien Spronck Over a year ago

@PeterWood ... just corrected that by stripping the strings first

AndreyT · Accepted Answer · 2016-02-29 10:59:59Z

2

You can use filter:

for words in list_of_lists: 
    words[:] = list(filter(lambda x: ' ' in x.strip(), words))

Or list comprehension:

for words in list_of_lists:
    words[:] = [x for x in words if ' ' in x.strip()]

edited Feb 29, 2016 at 10:59

answered Feb 18, 2016 at 14:19

AndreyT

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Comments

Tony Babarino · Accepted Answer · 2016-02-18 14:23:22Z

0

Functional programming way to do that:

>>> words
[['hey', 'hey you'], ['ok', 'ok no', 'boy', 'hey ma']]
>>> map(lambda v: ' '.join(v),
    filter(lambda y: len(y) > 1, map(lambda x: x.split(), words[1])))
['ok no', 'hey ma']
>>> map(lambda z: map(lambda v: ' '.join(v),
    filter(lambda y: len(y) > 1, map(lambda x: x.split(), z))), words)
[['hey you'], ['ok no', 'hey ma']]

answered Feb 18, 2016 at 14:23

Tony Babarino

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wpercy · Accepted Answer · 2016-02-18 14:25:17Z

-1

Here is the logic for each list, this you can loop and use

wordlist=['hey', 'hey you']
filter(None,  [ p if re.sub('\\b\\w+\\b', '', p) != '' else None for p in wordlist ])

output

['hey you']

edited Feb 18, 2016 at 14:25

wpercy

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answered Feb 18, 2016 at 14:24

Suresh Mali

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