Disassembling numbers from the same variable in javascript

Question

In JAVASCRIPT can each number from one variable be copied and transferred to another variable? for example:

var number = 2456;

Can you copy numbers from this variable (2, 4, 5 and 6) and each of them place in a new variable?

for example:

var a = 2;
var b = 4;
var c = 5;
var d = 6;

2456 is a single number. Numbers are represented as base 2 floating-point values. You can of course use the / and % operators to extract decimal digits from the value. — Pointy
– Pointy, Commented Feb 18, 2016 at 14:28

MysterX · Accepted Answer · 2016-02-18 14:57:35Z

2

I think it would be better to use an array instead of new variables. If so you can do this

var number = 2456,
    numbers = number.toString().split('').map(function(numberString){
       return Number(numberString);
    });

edited Feb 18, 2016 at 14:57

answered Feb 18, 2016 at 14:30

MysterX

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2 Comments

Felix Kling Over a year ago

There is no need for parseInt here. Use Number instead.

Felix Kling Over a year ago

Without new! That will return a number object instead of a primitive value.

S. Nadezhnyy · Accepted Answer · 2016-02-18 15:29:03Z

1

You can use this function :

var num = 123456;
NumberToArray(num);
alert(a);
alert(b);
alert(c);
alert(d);
function NumberToArray(num)
{
    var result = [];
    function div(val, by){  
        return (val - val % by) / by; 
    } 
    while (num != 0)
    {
        result.unshift(num%10);
        num = div(num, 10);
    }
    for (var i=0; i<result.length; i++)
    {
        window[String.fromCharCode(97+i)] = result[i]
    }
}

edited Feb 18, 2016 at 15:29

answered Feb 18, 2016 at 14:35

S. Nadezhnyy

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2 Comments

silver Over a year ago

are you sure this works , when i try to open it in chrome blank page appears?

MysterX Over a year ago

@silver, yep, because he used the array.shift method :-) array.unshift needed

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