subprocess call on python gives Error "Bad file descriptor"

Question

Whenever i call a c code executable from Python using the method below I get a "Bad file descriptor" error. When I run the code from the command prompt it works fine. Help please!?

import subprocess

p = subprocess.call(['C:\Working\Python\celp.exe', '-o', 'ofile'], stdin=subprocess.PIPE, stderr=subprocess.STDOUT)

In [84]: %run "C:\Working\Python\test.py"
Error: : Bad file descriptor

How do you know the program has been written in C and not in C++, Pascal, Modula, Fortran, Cobol or Brainfuck? — too honest for this site
– too honest for this site, Commented Feb 19, 2016 at 0:09
Please provide a traceback. What happend when you run this code outside of IPython? — Perry
– Perry, Commented Feb 19, 2016 at 0:41
1- use raw string literal for Windows paths (otherwise the backslash may have a special meaning inside a literal): r'C:\Users\..' 2- to discard possible input, use stdin=subprocess.DEVNULL — jfs
– jfs, Commented Feb 19, 2016 at 14:02
Update. I don't think this was a file descriptor error. i think this is a working directory error. The cwd of the subprocess shows as "/cygdrive/c/Working/Python" when it needs to be "C:/Working/Python". — sciguy
– sciguy, Commented Feb 22, 2016 at 22:08

MisterMiyagi · Accepted Answer · 2022-04-08 12:54:11Z

7

You forgot to add the stdout flag. add stdout = subprocess.PIPE, like this:

p = subprocess.call(
    ['C:\Working\Python\celp.exe', '-o', 'ofile'],
    stdin=subprocess.PIPE,
    stdout=subprocess.PIPE,  # needed for the next line to be sensible
    stderr=subprocess.STDOUT,
)

now, try run your script again

edited Apr 8, 2022 at 12:54

MisterMiyagi

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answered Jun 12, 2018 at 5:13

dvir

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Comments

Seekheart · Accepted Answer · 2016-02-18 23:34:48Z

-6

Try this

import subprocess

p = subprocess.call(['C:\Working\Python\celp.exe', '-o', 'ofile'], stdin=subprocess.PIPE, stderr=subprocess.STDOUT, shell = True)

answered Feb 18, 2016 at 23:34

Seekheart

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