xpath search attribute with part of string

Question

I am searching element like find_element_by_xpath('//a[@href="/requirements/22"]')

Can I search with only part of it. I mean instead of /requirements/22 something like *22?

find_element_by_xpath('//a[contains(@href,"22")]')

Padraic Cunningham
– Padraic Cunningham

2016-02-20 00:19:31 +00:00
Commented Feb 20, 2016 at 0:19 — Padraic Cunningham
– Padraic Cunningham, Commented Feb 20, 2016 at 0:19

Prateek · Accepted Answer · 2016-02-20 16:57:05Z

2

Contains :

find_element_by_xpath('//a[contains(@href, "22")]')

Starts With:

find_element_by_xpath('//a[starts-with(@href, "22")]')

Ends With:

find_element_by_xpath('//a[starts-with(@href, "22")]')

You are also free to try combinations, Example: find_element_by_xpath('//a[starts-with(@href, "22") and contains(@href, "req")]')

edited Feb 20, 2016 at 16:57

answered Feb 20, 2016 at 3:01

Prateek

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Comments

Andersson · Accepted Answer · 2016-02-20 00:19:54Z

2

Try this one:

find_element_by_xpath('//a[ends-with(@href, "22")]')

answered Feb 20, 2016 at 0:19

Andersson

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1 Comment

alecxe Over a year ago

ends-with() is not gonna work - it is a part of XPath 2.0.

Community · Accepted Answer · 2017-05-23 12:23:18Z

1

You would think of using ends-with(), but it is a part of 2.0 and is not going to work in your case.

Either use contains():

find_element_by_xpath('//a[contains(@href, "22")]')

Or, use ends-with CSS selector:

find_element_by_css_selector('a[href$=22]')

edited May 23, 2017 at 12:23

CommunityBot

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answered Feb 20, 2016 at 3:22

alecxe

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