Javascript clone without values

Question

After using clone() it cloning fields with values. I need to clone duplicate fields without values.

Javascript function:

$(document).ready(function(){
   $( ".add-row" ).click(function(){
      $( "ul.sea-service" ).first().clone().appendTo( ".personal-details1" );
   });
});

Also I've tried to add .val("") in following, but also unsuccessfully:

$(document).ready(function(){
   $( ".add-row" ).click(function(){
      $( "ul.sea-service" ).first().clone().val("").appendTo( ".personal-details1" );
   });
});

Have you any ideas?

Here is JS FIDDLE, try to enter any values and press +.

Possible duplicate: stackoverflow.com/questions/12035910/… — Matt
– Matt, Commented Feb 21, 2016 at 18:58
Possible duplicate of Jquery clone of a textbox without the content — Zakaria Acharki
– Zakaria Acharki, Commented Feb 21, 2016 at 19:02

Ibrahim Khan · Accepted Answer · 2016-02-21 18:59:54Z

3

Use .find('input').val('') like following.

$( ".add-row" ).click(function(){
  $( "ul.sea-service" ).first().clone().appendTo( ".personal-details1" ).find('input').val('');
});

UPDATED FIDDLE

answered Feb 21, 2016 at 18:59

Ibrahim Khan

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Comments

Nick · Accepted Answer · 2016-02-21 19:19:43Z

0

you have to find the inputs and empty them

$( "ul.sea-service" ).first().clone().appendTo( ".personal-details1" ).find('input').val("");

https://jsfiddle.net/c68jo3kr/2/

edited Feb 21, 2016 at 19:19

answered Feb 21, 2016 at 19:01

Nick

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2 Comments

Rino Raj Over a year ago

This is not working... Give some input an then clone. As per your answer the value will persist.

Nick Over a year ago

.find('input').val('') at the end does the job

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