Replace values in one column in multiple cells in array

Question

I'm trying to replace the 5th column in each cell in a cell array with the 5th column of each cell from another cell array. I made the following function, which does this but also replaces the values in all other columns with 0. How do I do this without deleting all other values from the other columns. The function is:

function [X]=replace_cells(cell) 
X={};
for i=1:length(cell)
   X{i}(:,[5])=cell{i}(:,[5]);
end

end

X has been initialized as an empty array. You are only copying the 5th column from each cell of cell into X so the other values can only be 0. I would also highly recommend not using cell as a variable name. — sco1
– sco1, Commented Feb 23, 2016 at 12:16

Rash · Accepted Answer · 2016-02-23 12:27:08Z

1

Your function doesn't replace the columns because the function creates X while it should be an input, try this function,

function X = replace_cells(c,X) 
for i = 1 : length(c)
   X{i}(:,5)=c{i}(:,5);
end

cell is a Matlab function don't use it as name for variables.

edited Feb 23, 2016 at 12:27

answered Feb 23, 2016 at 12:17

Rash

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2 Comments

user2271770 Over a year ago

This doesn't do what you say it does. Arguments (if they are not handle objects) are copied into the function's workspace, which means that your function will alter a copy, not the original. If you want to fix it you should declare your function like this function X=replace_cells(c,X).

Daniel Over a year ago

There is probably a return argument missing.

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