Running Command Line from C# without Window and Getting Output [duplicate]

Question

I am trying to run a command line script from C#. I want it to run without a shell and place the output into my string output. It doesn't like the p.StartInfo line. What am I doing wrong? I am not running a file like p.StartInfo.FileName = "YOURBATCHFILE.bat" like How To: Execute command line in C#, get STD OUT results. I need to set the "CMD.exe" and command line string. I have tried p.Start("CMD.exe", strCmdText); but that gives me the error: "Memer 'System.Diagnostics.Process.Start(string,string)' cannot be accessed with an instance reference; qualify it with a type name instead."

    string ipAddress;
    System.Diagnostics.Process p = new System.Diagnostics.Process();
    p.StartInfo.UseShellExecute = false;
    p.StartInfo.RedirectStandardOutput = true;
    string strCmdText;
    strCmdText = "tracert -d " + ipAdress;
    p.StartInfo("CMD.exe", strCmdText);
    string output = p.StandardOutput.ReadToEnd();
    p.WaitForExit();

Can you provide a program to us that builds? I'm 99% sure this one doesn't — Joe Phillips
– Joe Phillips, Commented Feb 23, 2016 at 15:35
"It doesn't like the p.StartInfo line." Exactly what is the error? — kjbartel
– kjbartel, Commented Feb 23, 2016 at 15:35
No, it doesn't and won't run, because the IP addresses are specific to my machine, and the p.StartInfo won't compile anyways. It says it "cannot be used like a method". — Sean
– Sean, Commented Feb 23, 2016 at 15:37
Your answer is the second answer to the other question which this question is a duplicate of. You don't even need "cmd.exe" anyway. — kjbartel
– kjbartel, Commented Feb 23, 2016 at 15:47

Zwo · Accepted Answer · 2016-02-23 16:06:59Z

8

This code gives me the correct ouput.

const string ipAddress = "127.0.0.1";
Process process = new Process
{
    StartInfo =
    {
        UseShellExecute = false,
        RedirectStandardOutput = true,
        RedirectStandardError = true,
        CreateNoWindow = true,
        FileName = "cmd.exe",
        Arguments = "/C tracert -d " + ipAddress
    }
};
process.Start();
process.WaitForExit();
if(process.HasExited)
{
    string output = process.StandardOutput.ReadToEnd();
}

edited Feb 23, 2016 at 16:06

answered Feb 23, 2016 at 15:49

Zwo

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3 Comments

Sean Over a year ago

That was the format I was looking for. Thanks!

Sean Over a year ago

It gives me the error "StandardOut has not been redirected or the process hasn't started yet."

Zwo Over a year ago

@Sean Try the edited answer.

Serge · Accepted Answer · 2016-02-23 15:47:28Z

1

You are using StartInfo incorrectly. Have a look at documentation for ProcessStartInfo Class and Process.Start Method (). Your code should look something like this:

string ipAddress;
System.Diagnostics.Process p = new System.Diagnostics.Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
string strCmdText;
strCmdText = "/C tracert -d " + ipAdress;

// Correct way to launch a process with arguments
p.StartInfo.FileName="CMD.exe";
p.StartInfo.Arguments=strCmdText;
p.Start();


string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();

Also, note that I added /C argument to strCmdText. As per cmd /? help:

/C Carries out the command specified by string and then terminates.

edited Feb 23, 2016 at 15:47

answered Feb 23, 2016 at 15:41

Serge

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1 Comment

Sean Over a year ago

Yes, I tried that. It gives me the error "Member 'System.Diagnostics.Process.Start(string,string)' cannot be accessed with an instance reference; qualify it with a type name instead."

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