I need to rename a bunch of files in a folder with new name reference from a text file. Can you please give an example for this.
My New Names In a Text file:
1BA
1BB
1BC
1BD
1BE
1BF
1C0
1C1
1C2
1C3
Like this.
Updated Code:
import csv
import os
with open('names.txt') as f2:
filedata = f2.read().split(",")
os.rename(filedata[0].strip(), filedata[1].strip())
f2.close()
f2 = open ('Lines.txt','w')
f2.write(filedata)
f2.close()
What about using a CSV (comma separated) file for input in the format oldPath, newPath and do the following:
import csv
import os
with open('names.csv') as csvfile:
reader = csv.reader(csvfile)
for row in reader:
oldPath = row[0]
newPath = row[1]
os.rename(oldPath, newPath)
Alternatively, if you want to move the file to another directory/filesystem you can have a look at shutil.move
os.rename again in a loop like: with open("names.txt") as f: for line in f: .... This is reading the file line by lineoldname, newname you will need parts = line.split(",") to separate old and new names and os.rename(parts[0].strip(), parts[1].strip()). The strip method will remove any whitespace characters around the name (like trailing ` ` ).
# Create old.txt and rename.txt
# Do not include file path inside the txt files
# For each line, write a filename include the extension
from pathlib import Path
import os
import sys
print("enter path of folder")
path = input()
oldList = []
with open(path + "\\old.txt", "r", encoding="utf8", errors='ignore') as readtxt:
for f in readtxt:
fname = f.rstrip()
oldList.append(fname)
# i is index of oldList
i = 0
newList = []
with open(path + "\\rename.txt", "r", encoding="utf8", errors='ignore') as readtxt:
for f in readtxt:
newName = f.rstrip()
os.rename(path + "\\" + oldList[i], path + "\\" + newName)
i += 1
